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BaLLatris [955]
3 years ago
12

What is the answer to 3/4 divided by 2 and 1/2 as a fraction ​

Mathematics
1 answer:
kramer3 years ago
4 0

Answer:

3/10

Step-by-step explanation:

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How do I solve this problem
tino4ka555 [31]

Answer:

0.6

Step-by-step explanation:

2x3 add 1 power of 10 to the 3 you get 6 and now you just remove/divide the power of 10 you added and you get .6

7 0
3 years ago
A group of people were given a personality test to determine if they were Type A or Type B. The results are shown in the table b
aalyn [17]
D) there is not enough information
7 0
3 years ago
Solve:<br><img src="https://tex.z-dn.net/?f=%20%5Cfrac%7Bzz%7D%7B4%7D%20%20%2B%205%20%5Cgeqslant%205.5" id="TexFormula1" title="
allochka39001 [22]

\bf \cfrac{zz}{4} + 5\geqslant 5.5\implies \stackrel{\textit{subtracting 5 from both sides}}{\cfrac{zz}{4}\geqslant 0.5}\implies \stackrel{\textit{multiplying both sides by 4}}{zz \geqslant 2}

7 0
3 years ago
What is the area of this parallelogram?
LuckyWell [14K]
A = bh 

b = 7 + 4 = 11
h = 8

11(8) = 88

The correct answer is B. 88 m^2
6 0
3 years ago
Read 2 more answers
HELP URGENT. The following sphere has a diameter of 18 cm. What is the volume of the sphere? Use 3.14 for and round your answer
Trava [24]

The volume of the sphere with the given value of diameter is to the nearest tenth is 3052.1cm³.

Option C is the correct answer.

<h3>What is the volume of the sphere?</h3>

The volume of  the sphere is the amount of space occupied within the sphere.

Volume of sphere is expressed as;

V = (4/3)πr³

Where r is the radius and π is pi ( π = 3.14 )

Given that;

  • Diameter of the sphere d = 18cm
  • Radius r = d/2 = 18cm/2 = 9cm
  • Constant pi π = 3.14
  • Volume V = ?

V = (4/3)πr³

V = (4/3) × 3.14 × 9cm)³

V = (4/3) × 3.14 × 729cm³

V = 3052.1cm³

Therefore, the volume of the sphere with the given value of diameter is to the nearest tenth is 3052.1cm³.

Option C is the correct answer.

Learn more about volume of hemisphere here: brainly.com/question/3362286

#SPJ1

6 0
2 years ago
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