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AVprozaik [17]
3 years ago
7

A football kicked straight up from the ground With an initial velocity of 32 ft/s returned to the ground after 2 s. The height o

f the projectile t seconds after launch is modeled by the function f(x)=-16x^2+32x. What is the maximum height of the projectile in feet? Show your work
Mathematics
1 answer:
horsena [70]3 years ago
4 0
Maximum height is 16 ft :
f(x)=ax²+bx+c
t max= -b/(2a)=-32/(2×-16)=1 sec
plug it back in the equation = -16+32=16ft
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rewona [7]

Answer:

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

Try rearranging and factoring -8y-2c-2b-8x-2a:

This is equal to -8(x + y) -2(a + b + c).

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and since a + b + c = 8, we end up with:

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