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Julli [10]
3 years ago
6

HELP ASAP plz!! Find the value of each variable

Mathematics
1 answer:
Mamont248 [21]3 years ago
3 0

Answer:y=12.1244

X=24.2487

Step-by-step explanation:

SOHCATOA or you could have used Pythagorean theorem after you found one of the sides, but I find that it’s quicker to use this.

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What are all the real zeros
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For this case we have a function of the form y = f (x), wheref (x) = (x-12) ^ 3-10

To find the real zeros we must equal zero and clear the variable "x".

(x-12) ^ 3-10 = 0

We add 10 to both sides of the equation

(x-12) ^ 3-10 + 10 = 10\\(x-12) ^ 3 = 10

We apply cube root to both sides of the equation:

\sqrt[3]{(x-12)^3} = \sqrt[3] {10}\\x-12 = \sqrt[3] {10}

We add 12 to both sides of the equation:

x-12 + 12 = \sqrt[3] {10} +12\\x = \sqrt[3] {10} +12

Answer:

Option D

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Harlamova29_29 [7]
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The perimeters of square region S and rectangular region R are equal. If the sides of R are in the ratio 2 : 3, what is the rati
Ksivusya [100]
<h2>Answer:</h2>

The ratio of the area of region R to the area of region S is:

                    \dfrac{24}{25}

<h2>Step-by-step explanation:</h2>

The sides of R are in the ratio : 2:3

Let the length of R be: 2x

and the width of R be: 3x

i.e. The perimeter of R is given by:

Perimeter\ of\ R=2(2x+3x)

( Since, the perimeter of a rectangle with length L and breadth or width B is given by:

Perimeter=2(L+B) )

Hence, we get:

Perimeter\ of\ R=2(5x)

i.e.

Perimeter\ of\ R=10x

Also, let " s " denote the side of the square region.

We know that the perimeter of a square with side " s " is given by:

\text{Perimeter\ of\ square}=4s

Now, it is given that:

The perimeters of square region S and rectangular region R are equal.

i.e.

4s=10x\\\\i.e.\\\\s=\dfrac{10x}{4}\\\\s=\dfrac{5x}{2}

Now, we know that the area of a square is given by:

\text{Area\ of\ square}=s^2

and

\text{Area\ of\ Rectangle}=L\times B

Hence, we get:

\text{Area\ of\ square}=(\dfrac{5x}{2})^2=\dfrac{25x^2}{4}

and

\text{Area\ of\ Rectangle}=2x\times 3x

i.e.

\text{Area\ of\ Rectangle}=6x^2

Hence,

Ratio of the area of region R to the area of region S is:

=\dfrac{6x^2}{\dfrac{25x^2}{4}}\\\\=\dfrac{6x^2\times 4}{25x^2}\\\\=\dfrac{24}{25}

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