Answer:
31.5mL
Explanation:
The following were obtained from the question:
C1 (concentration of stock solution) = 2M
V1 (volume of stock solution) =.?
C2 (concentration of diluted solution) = 0.630M
V2 (volume of diluted solution) = 100mL
Using the dilution formula C1V1 = C2V2, the volume of the stock solution needed can be obtained as follow:
C1V1 = C2V2
2 x V1 = 0.630 x 100
Divide both side by 2
V1 = (0.630 x 100) /2
V1 = 31.5mL
Therefore, 31.5mL of 2M solution of FeCl2 required
Erm i’m afraid we need the list
Answer: I believe the answer is Hydrobromic Acid. Strong Acids are considered to ionize.
Avagadros number states that 1 mol of any substance is made of 6.022 x 10^23 units
These units could be atoms making up elements or molecules making up compounds
Therefore 1 mol of CoCl2 is Made of 6.022 x 10^23 molecules of CoCl2
Molar mass of CoCl2 is 130 g/mol
Therefore 1 mol of CoCl2 weighs 130 g
So 130 g of CoCl2 contains 6.022 x 10^23 Molecules of CoCl2
Then 240 g of CoCl2 contains - 6.022 x 10^23 / 130 g x 240 g = 1.11 x 10^24 molecules of CoCl2
Answer is 1.11 x 10^24 molecules of CoCl2