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valentinak56 [21]
3 years ago
6

Following a volcanic eruption, which event is usually the last one to be observed

Chemistry
2 answers:
oee [108]3 years ago
6 0

Answer:

the last thing to bee observed is the damage

Explanation:

A volcanic event occurs when there is a sudden or continuing release of ... (1) an eruptive pulse (essentially an explosion with an eruption plume, but also ... events like caldera collapse, or long erosional intervals, and may last 10 m.y. or more ... where a certain type of behavior was first observed or most commonly occurs.

emmainna [20.7K]3 years ago
4 0

Answer: observing it

Explanation:

I got it right on test

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I would say an airport

Explanation:

why because it is ran by the government

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We know this by analyzing the scientific formulas created to measure the velocity of an object. The formula for this is \frac{d}{t} , meaning displacement over a period of time. Since option 3 described this equation perfectly, we can say that this is the correct option.

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2 years ago
The amount of I−3(aq) in a solution can be determined by titration with a solution containing a known concentration of S2O2−3(aq
Pavlova-9 [17]

Answer : The molarity of I_3^- in the solution is, 0.128 M

Explanation :

The given balanced chemical reaction is,

2S_2O_2^{-3}(aq)+I_3(aq)\rightarrow S_4O_2^{-6}(aq)+3I^-(aq)

First we have to calculate the moles of Na_2S_2O_3.

\text{Moles of }Na_2S_2O_3=\text{Molarity of }Na_2S_2O_3\times \text{Volume of solution}

\text{Moles of }Na_2S_2O_3=0.260mole/L\times 0.0296L=0.007696mole

Conversion used : (1 L = 1000 ml)

Now we have to calculate the moles of I_3^-.

From the balanced chemical reaction, we conclude that

As, 2 moles of S_2O_2^{-3} react with 1 mole of I_3^-

So, 0.007696 moles of S_2O_2^{-3} react with \frac{0.007696}{2}=0.003848 mole of I_3^-

The moles of I_3^- = 0.003848 mole

Now we have to calculate the molarity of I_3^-.

\text{Molarity of }I_3^-=\frac{\text{Moles of }I_3^-}{\text{Volume of solution}}

Now put all the given values in this formula, we get:

\text{Molarity of }I_3^-=\frac{0.003848mole}{0.03L}=0.128mole/L=0.128M

Therefore, the molarity of I_3^- in the solution is, 0.128 M

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Can someone help me out real quick? Thanks!
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I think the answer is B.

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