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rjkz [21]
3 years ago
9

#1: 2H2O + 2K (s) 2KOH (l) + 2H2 (g) is an example of which type of reaction?

Chemistry
2 answers:
mihalych1998 [28]3 years ago
7 0
D. Double-displacement
abruzzese [7]3 years ago
6 0

Answer:

D) double-displacement

Explanation:

In a displacement reaction, one or more atoms replace one or more atoms of a given molecule to form a new one.

In this case, two atoms of K replace two atoms of H in the water molecules two form H2 and KOH.

Is double because two displacement happen in the global reaction equation.  

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Identify each of the following compounds as: (a) a nonelectrolyte: lactose (c12h22o11) potassium chloride (kcl) lactic acid (hc3
11Alexandr11 [23.1K]

Nonelectrolytes are compounds that do not tend to get ionize in all solution. As a result, solutions which contains nonelectrolytes will not conduct electricity.

Ionic compounds dissolve in water and break into the constituent ions through the process called ionization. Now These electrolyte solutions can either be acids, or bases, or salts.

If  the process of ionization produces a large no. of ions in the solution, it is a strong electrolyte. On the other hand, if it produces only a few ions, the solution is a weak electrolyte,

Potassium chloride (KCL) is a strong electrolyte,

Lactic acid (HC3H503) is a weak electrolyte,

Whereas, Ethanol (C3H7OH) is a non electrolyte,

Dimethylamine (CH3)2NH is a weak electrolyte,

Sodium hydroxide(NaOH) is a strong electrolyte.

To learn more about nonelectrolytes, head here

brainly.com/question/3712208

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6 0
1 year ago
The characteristic flame test colors of metal ions are due to atomic emission spectra. Duscuss the relationship between the abso
vesna_86 [32]

The characteristics flame test color of metal ions are because of the atomic emission spectra.  

When an atom absorbs a particular wavelength radiation, the electrons within it, move from lower energy level to the higher level of energy. Such a procedure is called absorption. When this stimulated electron to come back to its ground state, it loses energy in particular color on the basis of the frequency of the absorbed radiation. Such a procedure is called emission.  

As an atom exhibit, distinct levels of energy, the level close to the nucleus possess less energy in comparison to the level, which is far from the nucleus. So, electrons move from lower energy level to the higher level by attaining particular energy, and after excitation, it comes back from high energy level to a low energy level with the emission of light.  

According to Planck's concept, there is a specific difference of energy between the two energy level, so such energy difference is quantized. Only those radiation are absorbed, which are equivalent to the difference of energy between the two levels.  


8 0
3 years ago
An ionic bond is _?_
lubasha [3.4K]
It would be C, because Ionic bonds have to deal with valence electrons ( the outer shell ones) 
8 0
3 years ago
Which describes a property of all elements?
Kaylis [27]
This would be c as for the amswer
3 0
3 years ago
calculate the difference in slope of the chemical potential against temperature on either side of the normal freezing point of w
kipiarov [429]

Answer:

(a) The normal freezing point of water (J·K−1·mol−1) is -22Jmole^-^1k^-^1

(b) The normal boiling point of water (J·K−1·mol−1) is -109Jmole^-^1K^-^1

(c) the chemical potential of water supercooled to −5.0°C exceed that of ice at that temperature is  109J/mole

Explanation:

Lets calculate

(a) - General equation -

      (\frac{d\mu(\beta )}{dt})p-(\frac{d\mu(\alpha) }{dt})_p = -5_m(\beta )+5_m(\alpha ) =  -\frac{\Delta H}{T}

 \alpha ,\beta → phases

ΔH → enthalpy of transition

T → temperature transition

 (\frac{d\mu(l)}{dT})_p -(\frac{d\mu(s)}{dT})_p == -\frac{\Delta_fH}{T_f}

            = \frac{-6.008kJ/mole}{273.15K} ( \Delta_fH is the enthalpy of fusion of water)

           = -22Jmole^-^1k^-^1

(b) (\frac{d\mu(g)}{dT})_p-(\frac{d\mu(l)}{dT})_p= -\frac{\Delta_v_a_p_o_u_rH}{T_v_a_p_o_u_r}

                                  = \frac{40.656kJ/mole}{373.15K} (\Delta_v_a_p_o_u_rH is the enthalpy of vaporization)

                               = -109Jmole^-^1K^-^1

(c) \Delta\mu =\Delta\mu(l)-\Delta\mu(s) =-S_m\DeltaT

[\mu(l-5°C)-\mu(l,0°C)] =  [\mu(s-5°C)-\mu(s,0°C)]=-S_mΔT

\mu(l,-5°C)-\mu(s,-5°C)=-Sm\DeltaT [\mu(l,0

\Delta\mu=(21.995Jmole^-^1K^-^1)\times (-5K)

     = 109J/mole

6 0
2 years ago
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