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3 years ago

#1: 2H2O + 2K (s) 2KOH (l) + 2H2 (g) is an example of which type of reaction?

Chemistry

2 answers:

mihalych1998 [28]3 years ago

7 0

D. Double-displacement

abruzzese [7]3 years ago

6 0

Answer:

D) double-displacement

Explanation:

In a displacement reaction, one or more atoms replace one or more atoms of a given molecule to form a new one.

In this case, two atoms of K replace two atoms of H in the water molecules two form H2 and KOH.

Is double because two displacement happen in the global reaction equation.

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A food item that is left out of the refrigerator turns brown and forms bubbles and gas. What are the signs that this is a chemic

marshall27 [118]

Answer:

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3 years ago

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What is the solar mass of CHCI3?

4vir4ik [10]

Molar mass of CHCl3 is

sum of atomic mass of all the atoms in it.

= C + H + 3 Cl

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3 years ago

Socratic an example of an atom that has no charge is one that has

aksik [14]

An example of an atom that has no charge is one that has a. 2 protons, 2 electrons, and 1 neutron.

To be neutral an atom must have the <em>same number</em> of protons (+) and electrons (-).

Only then will the <em>charges cancel</em> and give a neutral atom.

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4 years ago

At STP, which sample contains the same number of molecules as 11.2 liters of CO2(g) at STP?

Lana71 [14]

The answer is (3) 11.2 L of N2(g). When the choices are all gases, the number of molecules depends on the molar number of the gas. Under the condition of STP, the molar number of a gas is depends on volume only. So the same volume of gas has the same number of molecules.

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4 years ago

What is the energy required to remove the electron from a hydrogen atom in the n = 11 state?

zaharov [31]

Based on the data given, the energy required to remove an electron from a hydrogen atom in the n = 11 state is -0.112 eV

<h3>What is ionization energy?</h3>

Ionization energy is the energy requiredto remove an electron from a neutral atom or a cation in its gaseous state.

To calculate the energy required to remove the electron from a hydrogen atom in the n = 11 state, the formula below is used:

$E_n = \frac{E_0 × Z^{2}}{n^{2}}$

where

$E_0 \: is \: ground \: state \: energy \: of \: hydrogen \: atom \: = -13.6 eV \\$

Z = 1
n = 11

substituting the values:

$E_n = \frac{ - 13.6 × 1^{2}}{11^{2}} \: = - 0.112 \: eV$

Therefore, the energy required to remove an electron from a hydrogen atom in the n = 11 state is -0.112 eV

Learn more about ionization energy at: brainly.com/question/1445179

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2 years ago