Quadratic formula is x = -b+ or- sq rt b^2-4ac / 2a
a=2 b=5 c=-3
-5 +or- sqrt 5^2-4(2)(-3) / 2(2)
-5 +or- sqrt 49/ 4
-5 + 7 /4 = 2/4 = 1/2
-5 - 7 /4 = -12/4 = -3
Factoring a*c is 2*-3 =-6
Factors of -6 that add to 5 are 6 and -1
Split 5x into +6x-1x
2x^2+6x-1x-3 and group
2x(x+3)-1(x+3)
(x+3)(2x-1)=0
x+3=0 gives x=-3
2x-1=0 gives x=1/2
By using simple rule of three, a period of 9.5 years on Venus is equivalent to 2134.65 terrestrial days.
<h3>How many terrestrial days are equivalent time in Venus?</h3>
One year on Earth is equivalent to 365.3 days and one year on Venus is equivalent to 224.7 days, the equivalent terrestrial time of 9.5 years on Venus is found by simple rule of three:
x = 9.5 yr × (224.7 days / 1 yr)
x = 2134.65 days
A period of 9.5 years on Venus is equivalent to 2134.65 terrestrial days.
To learn more on simple rule of three: brainly.com/question/15209325
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Answer:
a^3 - b^3.
Step-by-step explanation:
Area = length * breadth
= (a - b)(a^2 + ab + b^2)
= a(a^2 + ab + b^2) - b(a^2 + ab + b^2)
= a^3 + a^2b + ab^2 - a^2b - ab^2 - b^3
Note: the 4 middle terms cancel out. So the answer is
a^3 - b^3.
Answer:
R (t) = 60 - 60 cos (6t)
Step-by-step explanation:
Given that:
R(t) = acos (bt) + d
at t= 0
R(0) = 0
0 = acos (0) + d
a + d = 0 ----- (1)
After 
seconds it reaches a height of 60 cm from the ground.
i.e
Recall from the question that:
At t = 0, R(0) = 0 which is the minimum
as such it is only when a is negative can acos (bt ) + d can get to minimum at t= 0
Similarly; 60 × 2 = maximum
R'(t) = -ab sin (bt) =0
bt = k π
here;
k is the integer
making t the subject of the formula, we have:
replacing the derived equation of k into R(t) = acos (bt) + d
Since we known a < 0 (negative)
then d-a will be maximum
d-a = 60 × 2
d-a = 120 ----- (3)
Relating to equation (1) and (3)
a = -60 and d = 60
∴ R(t) = 60 - 60 cos (bt)
Similarly;
For 
where ;
Then b = 6
∴
R (t) = 60 - 60 cos (6t)
