First department can choose the pair (delegate,alternate) by 7*6 = 42 ways.
Second department can choose the pair (delegate,alternate) by 10*9 = 90 ways.
Third department can choose the pair (delegate,alternate) by 6*5 = 30 ways.
Since these selections are INDEPENDENT, the resulting choice can be done in 42*90*30=113400
2c-9=c
-9=-c
9=c
Hope that helps!
Answer:
16.703
Step-by-step explanation:
right angle triangle thus we use puthagoras theorem to find the unknown length.
By converse of pythagoras theorem,
c² = a² + b²
c = √a² + b²
where c is the hypothenuse, a and b can be any 2 side of the right angle triangle
so x = √c² - a² = √ 20² - 11² ≈ 16.703 (or u can use calculator to find the long string of decimals and then round off on your own)
Answer:
(D) 98/73
Step-by-step explanation:
13(6x-8) = 5x-6
First,u expand the bracket, which gives u:
13 times 6x minus 13 (times) -8. Represented figuratively as:
13(x)6x - 13(x)-8 = 5x-6
⏩ 78x - 104 = 5x-6
Then,u collect like terms
78x - 5x = -6+104. (Note: the sign changes when it passes d equal to(=) sign)
73x = 98. (Note: Since 73 is carrying d variable x,we divide both side by 73)
Therefore,the answer = 98/73
ANSWER
66 cubic units
EXPLANATION
The volume of a triangular prism is the area of the triangular base times the height of the prism.
We calculate the volume using the formula:
![volume = \frac{1}{2} bh \times H](https://tex.z-dn.net/?f=volume%20%3D%20%20%5Cfrac%7B1%7D%7B2%7D%20bh%20%5Ctimes%20H)
where b=4 is the base of the triangle and h=3 is the height of the triangle.
H=11 is the height of the prism.
We substitute these values to get;
![volume = \frac{1}{2} \times 4 \times 3 \times 11](https://tex.z-dn.net/?f=volume%20%3D%20%20%5Cfrac%7B1%7D%7B2%7D%20%20%5Ctimes%204%20%5Ctimes%203%20%5Ctimes%2011)
![volume = 66 \: cubic \: \: units](https://tex.z-dn.net/?f=volume%20%3D%20%2066%20%5C%3A%20cubic%20%5C%3A%20%20%5C%3A%20units)