4 years ago

First round 7.954 to the nearest tenth than hundredths than ones

Mathematics

1 answer:

trapecia [35]4 years ago

6 0

Nearest tenth = 8.0

Nearest hundredth = 7.95

Nearest ones = 8

You might be interested in

in order to attend the carnival, students must pay a $5 admission fee plus $0.75 per ride ticket. How many tickets are purchased

kodGreya [7K]

141 tickets are purchased

7 0

3 years ago

Read 2 more answers

A cricket bat is bought for $350.

Luda [366]

15%= .15

.15 × $350= 52.50

$350 - 52.50= $297.50

3 0

4 years ago

Which statement correctly explains whether Limit of h (x) as x approaches 9 exists?

spayn [35]

Answer:

hope this helpw

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

What is the value of P

marysya [2.9K]

Answer:

121

Step-by-step explanation:

360-110-36-93=121

5 0

3 years ago

Solve the following quadratic by<br> completing the square.<br> y = x^2 - 6x+7

kozerog [31]

Answer:

$x= 3+\sqrt{2}, \quad x= 3 -\sqrt{2}$

Step-by-step explanation:

<u>Given quadratic equation</u>:

$y = x^2 - 6x+7$

To complete the square, begin by adding and subtracting the square of half the coefficient of the term in x:

$\implies y = x^2 - 6x+\left(\dfrac{-6}{2}\right)^2-\left(\dfrac{-6}{2}\right)^2+7$

$\implies y = x^2 - 6x+\left(-3\right)^2-\left(-3\right)^2+7$

$\implies y = x^2 - 6x+9-9+7$

Factor the perfect square trinomial:

$\implies y=(x-3)^2-9+7$

$\implies y=(x-3)^2-2$

To solve the quadratic, set it to zero and solve for x:

$\implies (x-3)^2-2=0$

$\implies (x-3)^2-2+2=0+2$

$\implies (x-3)^2=2$

$\implies \sqrt{(x-3)^2}=\sqrt{2}$

$\implies x-3= \pm\sqrt{2}$

$\implies x-3+3= 3\pm\sqrt{2}$

$\implies x= 3\pm\sqrt{2}$

Therefore, the solution to the given quadratic equation is:

$x= 3+\sqrt{2}, \quad x= 3 -\sqrt{2}$

6 0

1 year ago

Read 2 more answers