Answer:
<u><em>Hope it helped :)</em></u>
Step-by-step explanation:

Answer:
True
Step-by-step explanation:
Answer:
84 is the highest possible course average
Step-by-step explanation:
Total number of examinations = 5
Average = sum of scores in each examination/total number of examinations
Let the score for the last examination be x.
Average = (66+78+94+83+x)/5 = y
5y = 321+x
x = 5y -321
If y = 6, x = 5×6 -321 =-291.the student cannot score -291
If y = 80, x = 5×80 -321 =79.he can still score higher
If If y = 84, x = 5×84 -321 =99.This would be the highest possible course average after the last examination.
If y= 100
The average cannot be 100 as student cannot score 179(maximum score is 100)
Answer:
10th term means n = 10
we have general term = n² -8
substituting the value of n we get
10² - 8 = 100-8 =92
Step-by-step explanation:
Answer:
7
Step-by-step explanation:
→ Substitute x = -1 into - 5x + 2
-5 × -1 = 5
5 + 2 = 7