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3 years ago

A parabola has its vertex at (2, 1) and crosses the x-axis at (1,0) anu al l

Mathematics

1 answer:

Y_Kistochka [10]3 years ago

7 0

Answer:

Step-by-step explanation:

The equation of a parabola in vertex form is

y = a(x - h)² + k

where (h, k) are the coordinates of the vertex and a is a multiplier

Here (h, k) = (2, 1), thus

y = a(x - 2)² + 1

To find a substitute (1, 0) into the equation

0 = a(1 - 2)² + 1

0 = a + 1 ( subtract 1 from both sides )

a = - 1

Hence

y = - (x - 2)² + 1 or

y = 1 - (x - 2)² → A

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1 year ago

If cot theta= 4/3, find csc theta

Marrrta [24]

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Step-by-step explanation:

The trigonometric identity needed is:

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Substitute it into $csc^2\theta=cot^2\theta+1$ :

$csc^2\theta=(\frac{4}{3})^2+1$

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