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zhenek [66]
3 years ago
10

Find the y-intercept of the line: -4x - 2y = 16

Mathematics
1 answer:
Georgia [21]3 years ago
3 0
The y-intercept is (0, -8) 
if you set the equation to slope intercept format you get

y=-2x-8
You might be interested in
Given sin thata = 2/5 and 0° < thata < 90°. find sin 2 thata​
Andrej [43]

Recall the double angle identity:

\sin2\theta=2\sin\theta\cos\theta

With \theta measuring between 0º and 90º, we know \cos\theta>0. So from the Pythagorean identity, we get

\sin^2\theta+\cos^2\theta=1\implies\cos\theta=\sqrt{1-\sin^2\theta}=\dfrac{\sqrt{21}}5

Then

\sin2\theta=2\dfrac25\dfrac{\sqrt{21}}5=\dfrac{4\sqrt{21}}{25}

5 0
3 years ago
Five friends take a maths test
gulaghasi [49]

Answer:

Adam scored 60, Brandon scored 66, Chen scored 74, Damion scored 75, and Erica scored 75.

Step-by-step explanation:

Since five friends took the maths test, and Adam, Brandon, and Chen together together scored 200 marks; Brandon, Chen and Damion together scored 215; Chen, Damion and Erica together scored 224; and Damion and Erica scored more than Chen; While the five of them together scored 350 marks, to determine what are their individual scores the following calculations must be performed:

Adam + Brandon + Chen = 200

Damion + Erica = 150

Brandon + Chen + Damion = 215

Adam + Erica = 135

Chen + Damion + Erica = 224

Adam + Brandon = 126

Adam + Brandon = 126 + Chen = 200

Chen = 200 - 126

Chen = 74

Damion and Erica scored more than Chen

Chen + Damion + Erica = 224

74 + Damion + Erica = 224

Damion + Erica = 150

Damion = 75

Erica = 75

Brandon + Chen + Damion = 215

Brandon + 74 + 75 = 215

Brandon = 215 - 74 - 75

Brandon = 66

Adam = 350 - 75 - 75 - 74 - 66

Adam = 60

Therefore, Adam scored 60, Brandon scored 66, Chen scored 74, Damion scored 75, and Erica scored 75.

3 0
2 years ago
Soccer field dimensions according to FIFA must be no greater than 120 meters in length. What is the length of the field in kilom
Yuri [45]

Answer: 0.12 Kilometer

Step-by-step explanation:

120 divided by 1000

6 0
3 years ago
I need help with exercises 3,4, and 6 please show all work and don’t answer number 5 just tell me if it is correct
joja [24]
*If you need me to do #5, DM me!

3. 
The area of a triangle can be given by (just plug and chug as always):
A_t = \frac{1}{2} bh = \frac{1}{2}(3)(4) = 6ft^2
The area of the triangle is 6ft².

4. I will divide into a triangle and a rectangle (because the actual equation for the area of a pentagon requires it to be a perfect pentagon). Let's do the triangle first (height is 3 because you subtract 12 from 15):
A_t = \frac{1}{2} bh = \frac{1}{2}(8)(3) = 12m^2
A_r = bh = 12(8) = 96m^2
Now we just add them:
96+12 = 108m^2

So, the area of that pentagon is 108m².

5. You are actually wrong on this one because the area of a triangle is:
A_t = \frac{1}{2}bh
So, just halve your answer and it will be correct.

6. We can just split it into 4 triangles of equal area and then multiply the area of 1 triangle by 4 to get the total area. Let's do just that:
A_t = \frac{1}{2}bh = \frac{1}{2}(2.5)(5) = 6.25cm^2
Multiply by 4 to get total area:
6.25*4 = 25cm^2

So, the area of the given rhombus is 25cm².
8 0
3 years ago
Can someone please explain
ankoles [38]
Start by defining variables (things you don't know). Let's make:
t = number of true/false questions
m = number of multiple choice questions

Equation #1
total questions on the test (given to be 20) is then:
t + m = 20

Equation #2
Multiply the number of questions by the points it's worth to get the total points
3t + 11m = 100

Now, you can use substitution to combine the two equations.

t + m = 20
by subtracting m from both sides, equation 1# becomes..
t = 20 - m

substitute t for 20 - m in the second equation.
3(20 - m) + 11m = 100

Solve for m.
3(20 - m) + 11m = 100
60 - 3m + 11m = 100
8m = 100 - 60
8m = 40
m = 5

There are 5 multiple choice questions on the test.
Now use this to find t.
t + m = 20 
t + 5 = 20
t = 20 - 5
t = 15

there are 15 true/false questions on the test.
7 0
3 years ago
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