Answer:
All I can really do is state it differently <> 4.5q /9
X is 45, z is 45, and y is 90
Answer:
1200 ounces
Step-by-step explanation:
How much of an alloy that is 10% copper should be mixed with 600 ounce of an alloy that is 70%copper in order to get an alloy that is 30%copper?
Let us represent
Number of ounce of 10% copper = x
Hence, our Equation =
x × 10% + 600 × 70% = (x + 600) × 30%
0.1x + 420 = (x + 600)0.3
0.1x + 420 = 0.3x + 180
Collect like terms
0.3x - 0.1x = 420 - 180
0.2x = 240
x = 240/0.2
x = 1200 ounces
You can solve a system of three equations by multiplying each equation by a number that allows you to add or suvtract the same equation together by eliminating the x or y variable
