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aleksley [76]
3 years ago
11

5/6 as a decimal and terminating

Mathematics
1 answer:
Ipatiy [6.2K]3 years ago
6 0

5/6 = 0.833333 .... (non-terminating)

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On a linear X temperature scale, water freezes at −115.0°X and boils at 325.0°X. On a linear Y temperature scale, water freezes
belka [17]

Answer:

The current temperature on the X scale is 1150 °X.

Step-by-step explanation:

Let is determine first the ratio of change in X linear temperature scale to change in Y linear temperature scale:

r = \frac{\Delta T_{X}}{\Delta T_{Y}}

r = \frac{325\,^{\circ}X-(-115\,^{\circ}X)}{-25\,^{\circ}Y - (-65.00\,^{\circ}Y)}

r = 11\,\frac{^{\circ}X}{^{\circ}Y}

The difference between current temperature in Y linear scale with respect to freezing point is:

\Delta T_{Y} = 50\,^{\circ}Y - (-65\,^{\circ}Y)

\Delta T_{Y} = 115\,^{\circ}Y

The change in X linear scale is:

\Delta T_{X} = r\cdot \Delta T_{Y}

\Delta T_{X} = \left(11\,\frac{^{\circ}X}{^{\circ}Y} \right)\cdot (115\,^{\circ}Y)

\Delta T_{X} = 1265\,^{\circ}X

Lastly, the current temperature on the X scale is:

T_{X} = -115\,^{\circ}X + 1265\,^{\circ}X

T_{X} = 1150\,^{\circ}X

The current temperature on the X scale is 1150 °X.

5 0
3 years ago
How to find the long leg of 2√2 from a 30:60:90 triangle?
Komok [63]

check the picture below.

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3 years ago
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Mrs. porter's cat weighs 6kg. her dog weighs 22kg more than her cat. what is the total weight of her cat and dog?
yan [13]
Cat= 6kg
Dog = 6kg + 22kg
Total weight = 6kg + 6kg + 22kg
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8 0
3 years ago
1_9,644=100,000 to the nearest ten thousand
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119,644 is the answer I believe
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Which graph shows y=2⌊x⌋+1 ?
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Um... It's none.
Did you took a picture of the wrong question.
The answer of that question is the top second one.
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3 years ago
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