Answer:
y = -9/10x + 3/10 or y = 3/10(1 - 3x)
Step-by-step explanation:
Perpendicular lines have slopes that are negative reciprocals of one another
so slope of line w is -9/10
Using (-3,3) >> y = -9/10x + b
3 = -9/10(-3) + b
3 = 27/10 + b
b = 3 - 27/10 = 30/10 - 27/10 = 3/10
y = -9/10x + 3/10 or y = 3/10(1 - 3x)
The Answer is b: x = 18, y = -20
Proof:
Solve the following system:
{4 x + 3 y = 12 | (equation 1)
{7 x + 5 y = 26 | (equation 2)
Swap equation 1 with equation 2:
{7 x + 5 y = 26 | (equation 1)
{4 x + 3 y = 12 | (equation 2)
Subtract 4/7 × (equation 1) from equation 2:
{7 x + 5 y = 26 | (equation 1)
{0 x+y/7 = (-20)/7 | (equation 2)
Multiply equation 2 by 7:
{7 x + 5 y = 26 | (equation 1)
{0 x+y = -20 | (equation 2)
Subtract 5 × (equation 2) from equation 1:
{7 x+0 y = 126 | (equation 1)
{0 x+y = -20 | (equation 2)
Divide equation 1 by 7:
{x+0 y = 18 | (equation 1)
{0 x+y = -20 | (equation 2)
Collect results:
Answer: {x = 18, y = -20
The answer is -2.
im sorry if the work is messy.
See the attached figure
DB = 4 and DC = 6 , We need to find AD
Using <span>Euclid's theorem for the right triangle
</span><span>
</span><span>∴ DB² = AD * DC
</span><span>
</span><span>∴ 4² = AD * 6
</span><span>
</span><span>∴ 6 AD = 16
</span><span>
</span><span>
</span><span>
∴ AD = 16/6 = 8/3 ≈ 2.67</span>
We need to do a system of equations here.
x + y = 275 (if you travel <em>x</em> km by bike and <em>y </em>km by bus, then you travel 275 km as given in the problem)
y = x + 55 (the problem stated that they were bussed (y) the amount they biked plus 55 more km (x + 55))
The second equation is already solved for y. So, we can plug it in to the first equation.
x + (x + 55) = 275
2x + 55 = 275 [combine x terms]
2x = 220 [subtract 55 from both sides]
x = 110 [divide by 2 to isolate x and solve for it]
Now we know that x is 110, the distance they traveled by bike.
And that's what we needed to answer the problem!
