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3 years ago

How do you write 56% as a fraction in simplest form?

Mathematics

1 answer:

Alecsey [184]3 years ago

3 0

56% can be represented with 56/100. That fraction can be reduced (or simplified) to 14/25.

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The length of a rectangle is twice that of its width. If the area of the rectangle is 72 square inches, then find the length and

Blizzard [7]

Well, we should start by listing the factors

1,2,3,4,6,8,9,12,16,24,36,72

You can put these in pairs if it will help you,

1*72 2*36 3*24 4*16 6*12 8*9

If you look, you can see that in only one pair the length is twice the width.

So your answer is

W=6

L=12

6 0

2 years ago

How to solve a-2+3=-2

maria [59]

So cancel each equation terms on both sides of the equation and move constant to the right side and change its sign. So your answer is A=-3

Your welcome

5 0

3 years ago

an outlier may be defined as a data point that is more than 1.5 times the interquartile range below the lower quartile or is mor

Ira Lisetskai [31]

Supposing a normal distribution, we find that:

The diameter of the smallest tree that is an outlier is of 16.36 inches.

--------------------------------

We suppose that tree diameters are normally distributed with mean 8.8 inches and standard deviation 2.8 inches.

In a normal distribution with mean $\mu$ and standard deviation $\sigma$ , the z-score of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean.
After finding the z-score, we look at the z-score table and find the p-value associated with this z-score, which is the percentile of X.

In this problem:

Mean of 8.8 inches, thus $\mu = 8.8$ .
Standard deviation of 2.8 inches, thus $\sigma = 2.8$ .

The interquartile range(IQR) is the difference between the 75th and the 25th percentile.

25th percentile:

X when Z has a p-value of 0.25, so X when Z = -0.675.

$Z = \frac{X - \mu}{\sigma}$

$-0.675 = \frac{X - 8.8}{2.8}$

$X - 8.8 = -0.675(2.8)$

$X = 6.91$

75th percentile:

X when Z has a p-value of 0.75, so X when Z = 0.675.

$Z = \frac{X - \mu}{\sigma}$

$0.675 = \frac{X - 8.8}{2.8}$

$X - 8.8 = 0.675(2.8)$

$X = 10.69$

The IQR is:

$IQR = 10.69 - 6.91 = 3.78$

What is the diameter, in inches, of the smallest tree that is an outlier?

The diameter is 1.5IQR above the 75th percentile, thus:

$10.69 + 1.5(3.78) = 16.36$

The diameter of the smallest tree that is an outlier is of 16.36 inches.

A similar problem is given at brainly.com/question/15683591

3 0

2 years ago

At a picnic, hamburgers and hotdogs were consumed in the ratio 7 to 4. If 41 hamburgers were consumed, how many hot dogs were co

GrogVix [38]

The answer should be 19

8 0

2 years ago

Please help!

Ainat [17]

(x – h)^2 + (y – k)^2 = r^2

this equation is a derivative of the equation of a circle

x^2 + y^2 = r^2
This is from the origin. If we move the in x or y then the radius will change positions in x or y

with h = -3 and k = 1

we can plug in each set of numbers and solve.

we find Z to be on the circle edge!

8 0

3 years ago