The price of jacket was $24.54
Step-by-step explanation:
Let,
Cost of jacket = x
Cost of pair of shoes = y
According to given statement;
x+y=52.95 Eqn 1
x = y-3.87 Eqn 2
Putting value of x from Eqn 2 in Eqn 1

Dividing both sides by 2

Putting y=28.41 in Eqn 2,

The price of jacket was $24.54
Keywords: linear equation, division
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Answer:
1 3/4 cups is between the 13th and 15th lines from the bottom.
Step-by-step explanation:
The bottom of the cup has no line and corresponds to 0 eights.
1st line up: 1/8 cup
2nd line up: 2/8 cup this is also called 1/4 cup
3rd line up: 3/8 cup
4th line up: 4/8 cup this is also called 1/2 cup
5th line up: 5/8 cup
6th line up: 6/8 cup this is also called 3/4 cup
7th line up: 7/8 cup
8th line up: 8/8 cup this is also called 1 cup
9th line up: 9/8 cup
10th line up: 10/8 cup this is also called 1 1/4 cup
11th line up: 1 3/8 cup
12th line up: 1 4/8 cup this is also called 1 1/2 cup
13th line up: 1 5/8 cup
14th line up: 1 6/8 cup this is also called 1 3/4 cup
15th line up: 1 7/8 cup
16th line up: 1 8/8 cup this is also called 2 cups
1 3/4 cups is between the 13th and 15th lines from the bottom.
Answer: hi your question is incomplete below is the complete question
Use the Divergence Theorem to calculate the surface integral S F dS with F x y z = , , and S is a sphere centered at the origin with a radius of 2. Confirm your answer by computing the surface integral
answer : surface integral = 384/5 π
Step-by-step explanation:
Representing the vector field as
F ( x, y , z ) = ( a^3 + y^3 ) + ( y^3 + z^3 ) + ( Z^3 + x^3 ) k
assuming the sphere ( s) with radius = 2 be centered at Origin of the vector field.
Hence the divergence will be represented as :
Attached below is the detailed solution
First we need to count the total number scores. This can be done from the stem and leaf plot. The total number of scores are 19. The total number of values is odd, so the median position will be:

Thus the 10th score is the median score for the class of Mr. Robert. The 10th score from the stem and leaf plot is 81.
Thus 81 is the median score of Mr. Robert's Class.