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3 years ago

Huilan is 15 years younger than Thomas. The sum of their ages is 65. What is Thomas's age?

Mathematics

2 answers:

Troyanec [42]3 years ago

4 0

Answer:

Thomas's age: 40

Step-by-step explanation:

We have:

Thomas's age - Huilan's age = 15 (1)

Thomas's age + Huilan's age = 65 (2)

Add 1 and 2 we have :

2T = 65+15

<=>2T = 80

$T=\frac{80}{2} =40$

So Thomas's age is 40.

<u><em>P/s: T is Thomas's age</em></u>

pashok25 [27]3 years ago

3 0

Answer:

40 years

Step-by-step explanation:

Hulian and Thomas together is 65 years

let us suppose hulian is X

now, so Thomas is x+15

so x+x+15=65

so 2x = 65-15

2x=50

x=25

Hulian is 25

and Thomas is 25+15=40

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I need you to answer with a, b, c, d

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$\begin{gathered} ax^2+bx+c=0 \\ \\ x=\frac{-b\pm\sqrt[]{b^2-4ac}}{2a} \end{gathered}$

For the given function:

$f(x)=2x^2-10x-3$ $x=\frac{-(-10)\pm\sqrt[]{(-10)^2-4(2)(-3)}}{2(2)}$ $x=\frac{10\pm\sqrt[]{100+24}}{4}$ $\begin{gathered} x=\frac{10\pm\sqrt[]{124}}{4} \\ \\ x=\frac{10\pm\sqrt[]{2\cdot2\cdot31}}{4} \\ \\ x=\frac{10\pm\sqrt[]{2^2\cdot31}}{4} \\ \\ x=\frac{10\pm2\sqrt[]{31}}{4} \\ \end{gathered}$ $\begin{gathered} x_1=\frac{10}{4}+\frac{2\sqrt[]{31}}{4} \\ \\ x_1=\frac{5}{2}+\frac{\sqrt[]{31}}{2} \end{gathered}$ $\begin{gathered} x_2=\frac{10}{4}-\frac{2\sqrt[]{31}}{4} \\ \\ x_2=\frac{5}{2}-\frac{\sqrt[]{31}}{2} \end{gathered}$

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