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snow_lady [41]
3 years ago
15

The Sunday newspaper costs $2.10 issue delivered and the Saturday and weekday papers cost 40 cents per issue delivered how many

complete weeks can be purchased for $117.00
Mathematics
1 answer:
In-s [12.5K]3 years ago
6 0

26 weeks is what I got

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Gary has 5 3/5 acres of land. he uses 1/3 acres of the land for a shed a 1/6 of land for planting. how many acres of land does G
SVETLANKA909090 [29]

Answer:

6/10 or 6/1/10

Step-by-step explanation:

5 3/5 + 1/3 +1/6 =6/10 or 6/1/10

3 0
2 years ago
Calculate the values of x and y.
Oduvanchick [21]

Step-by-step explanation:

the dimension for the output isn't correct.

when u multiply 2x2 matrix by 2x1 matrix, the output matrix must have dimensions of 2x1

8 0
2 years ago
The probability that a randomly selected 3-year-old male chipmunk will live to be 4 years old is 0.96516.
mezya [45]

Using the binomial distribution, it is found that there is a:

a) The probability that two randomly selected 3-year-old male chipmunks will live to be 4 years old is 0.93153 = 93.153%.

b) The probability that six randomly selected 3-year-old male chipmunks will live to be 4 years old is 0.80834 = 80.834%.

c) The probability that at least one of six randomly selected 3-year-old male chipmunks will not live to be 4 years old is 0.19166 = 19.166%. This probability is not unusual, as it is greater than 5%.

-----------

For each chipmunk, there are only two possible outcomes. Either they will live to be 4 years old, or they will not. The probability of a chipmunk living is independent of any other chipmunk, which means that the binomial distribution is used to solve this question.

Binomial probability distribution  

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

C_{n,x} = \frac{n!}{x!(n-x)!}

The parameters are:

  • x is the number of successes.
  • n is the number of trials.
  • p is the probability of a success on a single trial.

In this problem:

  • 0.96516 probability of a chipmunk living through the year, thus p = 0.96516

Item a:

  • Two is P(X = 2) when n = 2, thus:

P(X = 2) = C_{2,2}(0.96516)^2(1-0.96516)^{0} = 0.9315

The probability that two randomly selected 3-year-old male chipmunks will live to be 4 years old is 0.93153 = 93.153%.

Item b:

  • Six is P(X = 6) when n = 6, then:

P(X = 6) = C_{6,6}(0.96516)^6(1-0.96516)^{0} = 0.80834

The probability that six randomly selected 3-year-old male chipmunks will live to be 4 years old is 0.80834 = 80.834%.

Item c:

  • At least one not living is:

P(X < 6) = 1 - P(X = 6) = 1 - 0.80834 = 0.19166

The probability that at least one of six randomly selected 3-year-old male chipmunks will not live to be 4 years old is 0.19166 = 19.166%. This probability is not unusual, as it is greater than 5%.

A similar problem is given at brainly.com/question/24756209

6 0
2 years ago
Two cylinders. The smaller cylinder has height labeled as 6 cm. The larger cylinder has height labeled as 18 cm.
Yakvenalex [24]

Answer: first option.

Step-by-step explanation:

You know that the height of the smaller cylinder is 6 cm and the height of the larger cylinder is 18 cm, then you can find the volume ratio. This  is:

Volume\ ratio=(\frac{6cm}{18cm})^3\\\\Volume\ ratio=\frac{1}{27}

Knowing that the volume of the larger cylinder is 40,635 cubic centimeters, you need to multiply it  by the volume ratio to find the volume of the smaller cylinder.

Therefore:

V_{smaller}=\frac{1}{27}(40,635\ cm^3)\\\\V_{smaller}=1,505\ cm^3

8 0
3 years ago
What is the least number of solution a quadratic system can have
Setler79 [48]
The least number of quadratic system can have is Two real solutions or no real solutions. 
8 0
3 years ago
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