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3 years ago

Which graph represents the line 10x + 5y = 20?

Mathematics

2 answers:

steposvetlana [31]3 years ago

7 0

10+5y=20
*Add 10x to each side
5y=20-10x
*Divide each side by 5
y=4-2x
y=-2x+4
*The -2 represents the slope, so for every 2 units it goes down, it moves to the right one unit
*The 4 represents the y-intercept (or where it crosses the y-axis)

vesna_86 [32]3 years ago

5 0

Answer:

Option 1.

Step-by-step explanation:

The given equation of the line is 10x + 5y = 20

Now we will convert this equation into y-intercept form

10x + 5y = 20

5y = 20 - 10x

y = $\frac{1}{5}$ (20 _ 10x)

= -2x + 4

y-intercept of the line is 4 which gives us hint that graph (1) or (2) may be the correct option.

Since slope is (-2)

So from graph (1) slope of the line passing through (0,4) and (-2,0) = $\frac{4.0}{0+2}$ = 2

Therefore, graph A is not the answer.

For graph (2) slope of the graphed line passing through (0,4) and (2,0) = $\frac{4-0}{0-2}$ = (-2)

So graph (2) is representing the line y = -2x +4

Option 1. is the answer.

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Find the other endpoint of the line segment with the given endpoint and midpoint.

Shtirlitz [24]

Answer:

endpoint is (29, -13)

Step-by-step explanation:

Formula for midpoint is $(\frac{x_{1} + x_{2} }{2} ,\frac{y_{1} + y_{2} }{2} )$

So, let $(x_{2} , y_{2} )$ be the coordinates of the endpoint you are looking for.

$x_{1} = -9$ and $y_{1} = 7$

$(\frac{-9 + x_{2} }{2} , \frac{7 + y_{2} }{2} )$ = (10, -3)

$\frac{-9 + x_{2} }{2} = 10$ $\frac{7 + y_{2} }{2} = -3$

-9 + $x_{2}$ = 20 7 + $y_{2} = -6$

$x_{2} = 29$ $y_{2} = -13$

endpoint is (29, -13)

6 0

3 years ago

What is the end behavior? 10 points!!

Colt1911 [192]

Given:

The given function is:

$f_1(x)=-3\cdot 2^{x-5}-4$

The graph of the function is given.

To find:

The end behavior of the given function.

Solution:

We have,

$f_1(x)=-3\cdot 2^{x-5}-4$

From the given graph it is clear that the function approaches to -4 at x approaches negative infinite and the function approaches to negative infinite at x approaches infinite.

$f_1(x)\to -4$ as $x\to -\infty$

$f_1(x)\to -\infty$ as $x\to \infty$

Therefore, the end behaviors of the given function are:

$f_1(x)\to -4$ as $x\to -\infty$

$f_1(x)\to -\infty$ as $x\to \infty$

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Answer:

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loris [4]

Answer:

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Step-by-step explanation:

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