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melisa1 [442]
3 years ago
15

Identify the domain and range of the function graphed below

Mathematics
1 answer:
Naddik [55]3 years ago
5 0
The domain would be all real numbers such that x \leq 4.
The range would be all real numbers such that y \geq 0.

The domain in these problems is always the x values that can be used in the equation. As you can see in the picture, the highest number used is 4. Any number after that will produce no y value. So we know the domain must be 4 or less. 

We do the same for the y value. Since 0 is the lowest number, we know it must be greater than or equal to 0. Also, especially in graphs like this, it is important to note that even though it doesn't look like the y is growing fast, since it goes on to infinity, it will eventually get infinitely high. 
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4 years ago
If the perimeter is 112,the width is 6times to get the length.what is the length?and the width?solve for an area
Romashka [77]

Answer:

The length of rectangle is 8  unit

The width of rectangle is 48  unit

The Area of rectangle is 384 unit²

Step-by-step explanation:

Given as :

The perimeter of rectangle = P = 112  unit

The width is 6 times the length

Let The length of rectangle = L  unit

Let The width of rectangle = W   unit

So, W = 6 × L      .........1

Let The Area of rectangle = A unit²

<u>Now, According to question </u>

∵ Perimeter of rectangle = 2 × Length + 2 × Breadth

Or, P = 2 × L + 2 × W

Or, 112 = 2 × L + 2 ×  6 × L              (from eq 1 )

Or, 112 = 2 × L + 12 × L

Or, 112 = 14 L

∴  L = \dfrac{112}{14}

i.e L = 8

So, The length of rectangle = L = 8  unit

Put the value of L into eq 1

∵ W = 6 × L

So, W = 6 × 8

i.e W = 48

So, The width of rectangle = W = 48  unit

<u>Again</u>

∵ The Area of rectangle = (Length × Width)  unit²

Or, A = L× W

Or, A = 8 × 48

i.e A = 384 unit²

So, The Area of rectangle = A =  384 unit²

Hence , The length of rectangle is 8  unit

The width of rectangle is 48  unit

The Area of rectangle is 384 unit²    Answer

7 0
3 years ago
What is the value of 2/13÷2/3
andreev551 [17]

Answer:

\frac{2}{13}/\frac{2}{3}\\  \frac{2}{13}*\frac{3}{2}\\\frac{3}{13}

Step-by-step explanation:

5 0
3 years ago
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