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RSB [31]
3 years ago
7

Please help me..stuck on problem.

Mathematics
1 answer:
Dvinal [7]3 years ago
4 0
7a
TSA = 2lw<span> + 2</span>lh<span> + 2</span><span>wh 
TSA = 140 + 70 + 100 = 310 ft^2

7b

310 x $4 =$1240
cost = </span>$1240

7c

V= wlh = <span>7×10×5 = </span><span>350 ft^3</span>

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See attachment file below.

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Is 6,11,17,... geometric in sequences
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5 0
3 years ago
4cos^2(x)-7cos(x)+3<br> Please help and explain how you did it :)
dangina [55]

I assume you're asked to solve

4 cos²(<em>x</em>) - 7 cos(<em>x</em>) + 3 = 0

Factor the left side:

(4 cos(<em>x</em>) - 3) (cos(<em>x</em>) - 1) = 0

Then either

4 cos(<em>x</em>) - 3 = 0   <u>or</u>   cos(<em>x</em>) - 1 = 0

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From the first case, we get

<em>x</em> = cos⁻¹(3/4) + 2<em>nπ</em>  <u>or</u>   <em>x</em> = -cos⁻¹(3/4) + 2<em>nπ</em>

and from the second,

<em>x</em> = <em>nπ</em>

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7 0
3 years ago
5. A solid has a circle of radius r as its base. All sections of the solid perpendicular to the diameter along the x-axis are is
AleksandrR [38]

Answer:

 \frac{16r^3}{3}

Step-by-step explanation:

In this cross sections problem, we can integrate from -r to +r (so that the integral covers the entire base of the solid).

\int\limits^r_a {2(x^2+r^2 )} \, dx

The formatting for the integral did not let me put -r on the lower bound, so i replaced it with a, just know that a represents -r here.

Evaluating the integral gives use that it is equal to;

\frac{16r^3}{3}

Caution: this answer may not meet your needs, but this is the answer I have come up with with the given information.

If you found this answer helpful please consider leaving 5 stars, giving it a like, or if you asked this question, mark this answer as Brainliest. Thanks!

4 0
3 years ago
5^4=625 in log form pls.
galben [10]

Answer:

log_{5}(625)=4\\

7 0
3 years ago
Read 2 more answers
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