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4 years ago

11

Which equation represents a line which is parallel to the line y=4x-8y=4x−8?

1 answer:

Mashutka [201]4 years ago

8 0

This line's slope-intercept form is y=4x-8.

The equation that makes it parallel to the line is y=4x+[Any number]

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Simplify 4-x squared ÷2x-x squared<br>

lana66690 [7]

Answer:

4- $\frac{x}{2}$ - $x^{2}$

Step-by-step explanation:

5 0

3 years ago

Dylan owes half as much money as he used to owe. If he used to owe $28, which of the following expressions would reflect how muc

Ivahew [28]

28/2 or 28 x (1/2)
You can either divide $28 by 2 or multiply it by (1/2)

3 0

3 years ago

Ramon read twice on Saturday. In the morning, he read for

LenKa [72]

Answer:

if the numbers are separated by a fraction bar the response should be 11/12th of an hour on Saturday.

Step-by-step explanation:

1/2=6/12

5/12+6/12=11/12

4 0

3 years ago

Q6: Which is the graph of the polar equation r=1/1-sin theta.

AveGali [126]

Answer:

The correct answer is C.

Step-by-step explanation:

The given equation is;

$r=\frac{1}{1-\sin(\theta)}$

This implies that;

$r(1-\sin(\theta)=1$

$r-r\sin(\theta)=1$

Let us write in Cartesian coordinates by substituting;

$r=\sqrt{x^2+y^2} ,y=r\sin(\theta)$

$\sqrt{x^2+y^2}-y=1$

$\sqrt{x^2+y^2}=y+1$

Square both sides;

$(\sqrt{x^2+y^2})^2=(y+1)^2$

This implies that;

$x^2+y^2=y^2+2y+1$

$x^2=2y+1$

$y=\frac{1}{2}x^2-\frac{1}{2}$

This is an equation of a parabola that opens upwards with a y-intercept of $-\frac{1}{2}$ .

The correct choice is C

4 0

4 years ago

If the world's population increased exponentially from 5.937 billion in 1998 to 7.238 billion in 2014 and continued to increase

horrorfan [7]

Answer: The world's population in 2015 would have been 7.333 billion.

Step-by-step explanation:

Since the increase in population is an exponential one. It then follows a geometric progression defined by, $T_{n}$ = $ar^{n - 1}$

Where $T_{n}$ is the nth term, <em>a</em> is the 1st term, <em>r</em> is the common ratio.

Therefore, the population in <u>1998</u> is the <u>first term</u> <em>a</em> = 5.937 billion. The population in <u>2014</u> corresponds to the <u>17th term </u>(i.e., <em>n </em>= 17) = 7.238 billion.

Hence, $T_{n}$ = $ar^{n - 1}$

7.238 billion = 5.937 billion × $r^{17 - 1}$

$r^{16}$ = (7.238 billion) ÷ (5.937 billion)

= 1.219

<em>r</em> = $\sqrt[16]{1.219}$

<em>r</em> = 1.0125

To get the population in 2015, which is the 18th term. We use

$T_{n}$ = $ar^{n - 1}$

$T_{18}$ = 5.937 billion × $1.0125^{18 - 1}$

= 5.937 billion × $1.0125^{17}$

= 5.937 billion × 1.235

$T_{18}$ = 7.333 billion

4 0

4 years ago

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