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3 years ago

Verify the identity sin^2(x/2)=(1-cosx)/2

Mathematics

1 answer:

horsena [70]3 years ago

5 0

Use the following identity:

cos(2x)=1-2sin^2(x)

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PLEASE HELPME QUICKLY QUICK

Svetlanka [38]

Okay. So no more than 660 minutes will be spent cutting the lawn. The sign will be less than or equal to. A and D are out, because those show greater than or equal to symbols, which is not what we're looking for. x represents the number of lawns mowed, which is an average of 40 minutes, and he will have done 110 minutes. The equation is 40x + 110 ≤ 660. The answer is C.

3 0

3 years ago

My club has 25 members. In how many ways can I choose members to form a 4-person executive committee?

Rama09 [41]

Answer: 12650

Step-by-step explanation:

It can be done in C25 4 = 25!/(25-4)!/4!= 25!/21!/(2*3*4)=

=22*23*24*25/24=22*23*25= 12650 variants

4 0

3 years ago

Answer the question in the photo

Lera25 [3.4K]

Answer: 3

Step-by-step explanation:

Take the y coordinates and divide two of them. Example: 6 ÷ 2 = 3

6 0

3 years ago

Denis, Vera, and Yash are rock climbers. Yash is connected to Vera by a

grin007 [14]

Answer:

$33.14\°$

Step-by-step explanation:

Let

Y ----> field of vision that Yash's camera would need

we know that

Applying the law of sines

$\frac{sin(Y)}{25}=\frac{sin(41\°)}{30}$

Solve for sin(Y)

$sin(Y)=\frac{sin(41\°)}{30}(25)$

$Y=sin^{-1}[\frac{sin(41\°)}{30}(25)]$

$Y=33.14\°$

8 0

3 years ago

Read 2 more answers

A) Use the method of cylindrical shells to find the volume of the solid obtained by rotating the region bounded by the given cur

Leno4ka [110]

(a) See the attached sketch. Each shell will have a radius y chosen from the interval [2, 4], a height of x = 2/y, and thickness ∆y. For infinitely many shells, we have ∆y converging to 0, and each super-thin shell contributes an infinitesimal volume of

2π (radius)² (height) = 4πy

Then the volume of the solid is obtained by integrating over [2, 4]:

$\displaystyle 4\pi \int_2^4 y\,\mathrm dy = 2\pi y^2\bigg|_{y=2}^{y=4} = 2\pi (4^2-2^2) = \boxed{24\pi}$

(b) See the other attached sketch. (The text is a bit cluttered, but hopefully you'll understand what is drawn.) Each shell has a radius 9 - x (this is the distance between a given x value in the orange shaded region to the axis of revolution) and a height of 8 - x ³ (and this is the distance between the line y = 8 and the curve y = x ³). Then each shell has a volume of

2π (9 - x)² (8 - x ³) = 2π (648 - 144x + 8x ² - 81x ³ + 18x ⁴ - x ⁵)

so that the overall volume of the solid would be

$\displaystyle 2\pi \int_0^2 (648-144x+8x^2-81x^3+18x^4-x^5)\,\mathrm dx = \boxed{\frac{24296\pi}{15}}$

I leave the details of integrating to you.

3 0

2 years ago