Step-by-step explanation:
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Answer:
-7-a
Step-by-step explanation:
2a-3a +5-12
-a - 7
or -7-a
Answer:
D
Step-by-step explanation:
Since BD and AE are parallel lines, then
∠BDC = ∠AED ( corresponding angles ), thus
4x - 5 = 97 - 2x ( add 2x to both sides )
6x - 5 = 97 ( add 5 to both sides )
6x = 102 ( divide both sides by 6 )
x = 17, hence
∠AED = 97 - 2x = 97 - (2 × 17) = 97 - 34 = 63°
∠BDE and ∠AED are same side interior angles and are supplementary, thus
10y - 3 + 63 = 180
10y + 60 = 180 ( subtract 60 from both sides )
10y = 120 ( divide both sides by 10 )
y = 12 → D
Y
A raiz quadrada de 14 seria 3.74165738677 ou 3.7
Arredondamos para 4 já q 7 é próximo de 10
When we Simplify [(x^2)^3 × 5x] / [6x^2 × 15x^3], the result obtained is (1/18)x^2
<h3>Data obtained from the question</h3>
- [(x^2)^3 × 5x] / [6x^2 × 15x^3]
- Simplification =?
<h3>How to simplify [(x^2)^3 × 5x] / [6x^2 × 15x^3]</h3>
[(x^2)^3 × 5x] / [6x^2 × 15x^3]
Recall
(M^a)^b = M^ab
Thus,
(x^2)^3 = x^6
- [(x^2)^3 × 5x] / [6x^2 × 15x^3] = [x^6 × 5x] / [6x^2 × 15x^3]
Recall
M^a × M^b = M^(a+b)
Thus,
x^6 × 5x = 5x^(6 + 1) = 5x^7
6x^2 × 15x^3] = (6×15)x^(2 + 3) = 90x^5
- [x^6 × 5x] / [6x^2 × 15x^3] = 5x^7 / 90x^5
Recall
M^a ÷ M^b = M^(a - b)
Thus,
5x^7 ÷ 90x^5 = (5÷90)x^(7 - 5) = (1/18)x^2
Therefore,
- [(x^2)^3 × 5x] / [6x^2 × 15x^3] = (1/18)x^2
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