All categories

3 years ago

a recipe calls for a tatol of 3 2/3 cups of flour and sugar. the recipe calls for 1/4 cups of sugar, how much flour is needed?

Mathematics

1 answer:

lesantik [10]3 years ago

6 0

3 8/12 - 3/12

3 5/12 cups of flour would be the correct answer for this equation.

You might be interested in

The diagram below shows a shaded parallelogram drawn inside a rectangle. Using Pythagoras, find the hypotenuse of triangle A and

Julli [10]

Answer: 5.9 cm for both triangles.

Step-by-step explanation:

Hi, since the situation forms 2 right triangles we have to apply the Pythagorean Theorem:

c^2 = a^2 + b^2

Where c is the hypotenuse of a triangle (the longest side of the triangle) and a and b are the other sides.

Replacing with the values given:

c^2 = 3^2 + 5^2

c^2 = 9+25

c^2 = 34

c = √34

c = 5.9 cm

Since both triangles are identical ( same side lengths) the hypotenuse is the same for both, 5.9 cm.

Feel free to ask for more if needed or if you did not understand something.

5 0

2 years ago

Find the value of PR if Q is between P and R when PQ=25, PQ=2x+1, and QR=x. X ат X=8

Eva8 [605]

Answer:

$PR = 37$

Step-by-step explanation:

Given

$PQ = 25$

$PQ = 2x +1$

$QR = x$

Required

Since Q is between the given points, then:

$PR = PQ + QR$

This gives:

$PR = 2x + 1 + x$

Collect like terms

$PR = 2x + x+ 1$

$PR = 3x + 1$

Next, solve for x

We have:

$PQ = 25$

$PQ = 2x +1$

This gives:

$2x + 1 = 25$

Collect like terms

$2x = 25 -1$

$2x = 24$

Divide by 2

$x = 12$

So:

$PR = 3x + 1$

$PR = 3 * 12 + 1$

$PR = 37$

7 0

2 years ago

What is the factorization of 729^15+1000

Nesterboy [21]

$\bf \textit{difference and sum of cubes} \\\\ a^3+b^3 = (a+b)(a^2-ab+b^2) \\\\ a^3-b^3 = (a-b)(a^2+ab+b^2) \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ \begin{cases} 729=27^2\\ \qquad (3^3)^2\\ 1000=10^3 \end{cases}\implies 729^{15}+1000\implies ((3^3)^2)^{15}+10^3 \\\\\\ ((3^2)^{15})^3+10^3\implies (3^{30})^3+10^3\implies (3^{30}+10)~~[(3^{30})^2-(3^{30})(10)+10^2] \\\\\\ (3^{30})^3+10^3\implies (3^{30}+10)~~~~[(3^{60})-(3^{30})(10)+10^2]$