Q1 of company A = 2.5
Q3 of company A = 8
Interquatile range = (Q3 - Q1)/2 = (8 - 2.5)/2 = 5.5/2 = 2.75
Q1 of company B = 2
Q3 of company B = 5.5
Interquatile range = (5.5 - 2)/2 = 3.5/2 = 1.75
Therefore, t<span>he interquartile range for Company A employees is 2 more than the interquartile range for Company B employees.</span>
A = 16 over 49
b= 2 then 1 over 10
Angle 5 = 117° because it is vertical to angle 8
Angle 7 = 63° because it is symmetrical to angle 5
Angle 6 = 63° because it is vertical to angle 7.
Angle 1 = 117° because it is corresponding to angle 5.
Angle 2 = 63° because it is corresponding to angle 6.
Angle 3= 117° because it is corresponding to angle 8.
Angle 4 = 63° because it is corresponding to angle 7.
Answer:
Mr Park has enough money to pay his rent.
Step-by-step explanation:
The amount of the monthly rent paid = $1000
The account balance after depositing the paycheck = $1441.33
Now, to pay the rent,account should have more than the rent money $1000
Also, $1441.33 > $1000
⇒ The amount in the bank after depositing the paycheck > The rent to be paid
Hence, Mr Park has enough money to pay his rent.
Step-by-step explanation:
Given that the graph shows the normal distribution of the length of similar components produced by a company with a mean of 5 centimeters and a standard deviation of 0.02 centimeters.
A component is chosen at random, the probability that the length of this component is between 4.98 centimeters and 5.02
=P(|z|<1) (since 1 std dev on either side of the mean)
=2(0.3418)
=0.6826
=68.26%
The probability that the length of this component is between 5.02 centimeters and 5.04 centimeters is
=P(1<z<2) (since between 1 and 2 std dev from the mean)
=0.475-0.3418
=0.3332
=33.32%
