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fenix001 [56]
3 years ago
8

The formula v=√64h can be used to find the velocity v in feet per second of an object that has fallen h feet. Find the velocity

of an object that has fallen 30 feet. Round your answer to the nearest hundredth.
A) 960 feet/sec
B) 43.82 feet/sec
C) 240 feet/sec
D) 350.54 feet/sec
Mathematics
1 answer:
zhuklara [117]3 years ago
4 0

Answer:

  B)  43.82 feet/sec

Step-by-step explanation:

Fill in the number and evaluate:

  v = √(64×30) = √1920 ≈ 43.82 . . . . ft/s

_____

Of course, √(64h) can be simplified to 8√h. You know that √30 lies between 5 and 6, so the velocity lies between 8·5 = 40 and 8·6 = 48. There is only one answer choice in that range.

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3 years ago
Please answer ASAP I will give you five stars
Nataliya [291]

Known :

r = 6

h = 8

Asked :

V = ...?

Answer :

V = ⅓πr²h

= ⅓ × 3.14 × 6² × 8

= ⅓ × 3.14 × 36 × 8

= 3.14 × 12 × 8

= 301.44 units²

= <u>3</u><u>0</u><u>0</u><u> </u><u>units²</u> (rounded)

So, the volume of the cone is 300 units²

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3 0
3 years ago
Use Lagrange multipliers to find the maximum and minimum values of
marusya05 [52]

The Lagrangian is

L(x,y,\lambda)=x+8y+\lambda(x^2+y^2-4)

It has critical points where the first order derivatives vanish:

L_x=1+2\lambda x=0\implies\lambda=-\dfrac1{2x}

L_y=8+2\lambda y=0\implies\lambda=-\dfrac4y

L_\lambda=x^2+y^2-4=0

From the first two equations we get

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Then

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At these critical points, we have

f\left(\dfrac2{\sqrt{65}},\dfrac{16}{\sqrt{65}}\right)=2\sqrt{65}\approx16.125 (maximum)

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5 0
3 years ago
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