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sergiy2304 [10]
3 years ago
11

Center: (-13, -14) Point on Circle: (-13, -19)

Mathematics
1 answer:
SpyIntel [72]3 years ago
4 0

Answer:

(X + 13)² + (Y + 14)² = 25

Step-by-step explanation:

(X - H)² + (Y - K)² = R²

According to this Circle Equation, all negative symbols give the OPPOSITE terms of what they really are, which is why you see a 13 and 14 in the parentheses [-(-13) = 13; -(-14) = 14]. So, you plug the center into the formula, where <em>H</em> is the <em>phase shift</em> [<em>horizontal shift</em>] and <em>K</em> is the <em>vertical </em><em>shift</em>. Now, to find the radius, we have to find the range in between the <em>K</em><em> </em>and the y-coordinate of the Point of the Circle, so we do this:

-14 + ? = -19

5 = ? [Radius]

Now that we have our radius, we need to square it, so 5² is 25, there R² is 25.

I am joyous to assist you anytime.

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Step-by-step explanation:

To solve this question, we need to understand skewness,the normal probability distribution and the central limit theorem.

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To undertand skewness, it is important to understand the concept of the median.

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Problems of normally distributed samples are solved using the z-score formula.

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(a) Is the distribution of scores on this nal exam symmetric, right skewed, or left skewed?

Mean = 70, median = 74. So the distribution is left-skewed.

(b) Would you expect most students to have scored above or below 70 points?

70 is below the median, which is 74.

50% score above the median, and 50% below. So 50% score above 74.

This means that we should expect most students to have scored above 70.

(c) Can we calculate the probability that a randomly chosen student scored above 75 using the normal distribution?

The scores are skewed, so we cannot calculate any probability for a single student.

(d) What is the probability that the average score for a random sample of 40 students is above 75?

Now we can apply the central limit theorem.

\mu = 70, \sigma = 10, n = 40, s = \frac{10}{\sqrt{40}} = 1.58

This probability is 1 subtracted by the pvalue of Z when X = 75. So

Z = \frac{X - \mu}{\sigma}

By the Central limit theorem

Z = \frac{X - \mu}{s}

Z = \frac{75 - 70}{1.58}

Z = 3.16

Z = 3.16 has a pvalue of 0.9992

1 - 0.9992 = 0.0008

0.08% probability that the average score for a random sample of 40 students is above 75

(e) How would cutting the sample size in half aect the standard error of the mean?

n = 40

s =  \frac{10}{\sqrt{40}} = 1.58

n = 20

s =  \frac{10}{\sqrt{20}} = 2.24

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