The answer is False.
The word "declining" means going down. So, in this case, the employees would go down or leave.
Answer:
Answered below
Explanation:
//Program is written in Python programming language
def charCnt( fileName, char){
if not fileName.exists( ):
return sys.exit(1)
else:
openFile = open("$fileName.txt", "r")
readFile = openFile.read( )
fileLength = len (readFile)
count = 0
for character in range(fileLength):
if readFile[character] == char:
count++
openFile.close( )
return count
}
OMR, OCR and MICR are all types of character and mark recognition devices. They are scanners <span>that are able to recognize special </span>characters and marks<span>.
</span>OMR stands for Optical Mark Recognition,which <span>senses the presence or absence of a mark.</span>
OCR stands for Optical Character recognition, which reads special preprinted characters by light source.<span>
MICR stands for Magnetic Ink Character Recognition, where </span><span>machine reads character made of ink containing magnetized particles.
</span>
Answer:
Option 1: May crash at runtime because it can input more elements than the array can hold
Explanation:
Given the code as follows:
- int[] a = {1, 3, 7, 0, 0, 0};
- int size = 3, capacity = 6;
- int value = cin.nextInt();
- while (value > 0)
- {
- a[size] = value;
- size++;
- value = cin.nextInt();
- }
From the code above, we know the <em>a</em> is an array with six elements (Line 1). Since the array has been initialized with six elements, the capacity of the array cannot be altered in later stage.
However, a while loop is created to keep prompting for user input an integer and overwrite the value in the array started from index 3 (Line 4- 9). In every round of loop, the index is incremented by 1 (Line 7). If the user input for variable <em>value</em> is always above zero, the while loop will persist. This may reach a point where the index value is out of bound and crash the program. Please note the maximum index value for the array is supposedly be 5.
<span> 13,000 is the same as 1.3 x 10^4</span>
