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Bess [88]
3 years ago
14

"You have an interface on a router with the IP address of 192.168.192.10/29. Including the router interface, how many hosts can

have IP addresses on the LAN attached to the router interface?"
Computers and Technology
1 answer:
SSSSS [86.1K]3 years ago
5 0

Answer:

6 hosts can have IP addresses on the LAN attached to the router interface

Explanation:

Given IP address

=> 192.168.192.10/29

It has a subnet mask of /29 which means it has 3 host bits. This is calculated by subtracting 29 from 32(number of bits in an IPV4)

Since there are 3 host bits,  the total number of possible addresses is given by

=> 2^{3} = 8 possible addresses.

Out of these 8 possible addresses, the first address will be the subnet id and the last address will be the broadcast address.

Therefore, there are only 6 addresses available for the hosts.

<em>Hope this helps!</em>

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What does a linear bus topology used to connect all network devices?
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What value(s) can be input into this code for the value of number that will cause the code in the loop to execute? Scanner keybo
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Write a static method that implements a recursive formula for factorials. Place this method in a test program that allows the us
matrenka [14]

Answer:

Written in Java

import java.util.*;

public class Main {

  public static int fact(int n) {

     if (n == 1)

        return n;

     else

        return n * fact(n - 1);

  }

  public static void main(String[] args) {

     int num;

     Scanner input = new Scanner(System.in);

     char tryagain = 'y';

     while(tryagain == 'y'){

     System.out.print("Number: ");

     num = input.nextInt();

     System.out.println(num+"! = "+ fact(num));

     System.out.print("Try another input? y/n : ");

     tryagain = input.next().charAt(0);

}        

  }

}

Explanation:

The static method is defines here

  public static int fact(int n) {

This checks if n is 1. If yes, it returns 1

     if (n == 1)

        return n;

If otherwise, it returns the factorial of n, recursively

     else

        return n * fact(n - 1);

  }

The main method starts here. Where the user can continue executing different values of n. The program keep prompting user to try again for another number until user signals for stoppage

  public static void main(String[] args) {

This declares num as integer

     int num;

     Scanner input = new Scanner(System.in);

This initializes tryagain as y

     char tryagain = 'y';

This checks if user wants to check the factorial of a number

     while(tryagain == 'y'){

This prompts user for input

     System.out.print("Number: ");

This gets user input

     num = input.nextInt();

This passes user input to the function and also prints the result

     System.out.println(num+"! = "+ fact(num));

This prompts user to try again for another value

     System.out.print("Try another input? y/n : ");

This gets user response

     tryagain = input.next().charAt(0);

}        

Download txt
4 0
2 years ago
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