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hjlf
3 years ago
6

______ is a customer-facing CRM application. FAQ Search SFA E-mail

Computers and Technology
1 answer:
Stolb23 [73]3 years ago
5 0

Answer: SFA(Sales force automation)

Explanation: SFA(Sales force automation) is the customer relationship management application for the establishing the relation with the customer point of view.

It is in the integrated form of application that works on the customer side along with the tools of the CRM. Sales force management system is also one of the name for the sales force automation.

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Tom is very curious as to whether terrorism is truly linked to levels of religiosity around the world. As such, he gathers data
Ede4ka [16]

Answer:

Macrosociology

Explanation:

Sociological perspective or perspectives on sociology is an implied definition on how sociologists study and creates theories systematically, through predetermined theories. There are two perspectives sociologists view subject matters, they are macrosociology and microsociology perspectives.

The microsociology perspective describes the symbolic interactionism of individuals as a unit.

The macrosociology perspective studies the functional and conflict theories, which are the interaction of individuals in groups or communities and their impact to the society.

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3 years ago
Who watches the show gravity falls, if you do, if you play the theme song for the first episode backwards you get a hiding messi
Yakvenalex [24]
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3 years ago
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What is the purpose of the making of Nintendo Switch?
Elden [556K]

Answer:

To create a console that is suitable for children and families.

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3 years ago
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Can some one please help The term career is usually applied to a what PLEASEEEEEEEEEEEE HEEEEELLLLLPPPPP MEEEEEE
Sati [7]

Answer:

Position that allows for professional growth and advancement

Explanation:

Career is referring to better pay than a job because it allows the person to grow professionally and that knowledge the person can show anywhere. For example, the teacher matches this term, because the teacher will always look forward to the advancement and things that would help others.

This kind of personal and professional growth is considering a journey because the person that is growing has to learn each day about different and helpful things.

7 0
3 years ago
1. Print out the string length of s1 2. Loop through characters in s2 with charAt() and display reversed string 3. Compare s2, s
konstantin123 [22]

Answer:

See explaination

Explanation:

public class StringLab9 {

public static void main(String args[]) {

char charArray[] = { 'C', 'O', 'S', 'C', ' ', '3', '3', '1', '7', ' ', 'O', 'O', ' ', 'C', 'l', 'a', 's', 's' };

String s1 = new String("Objected oriented programming language!");

String s2 = "COSC 3317 OO class class";

String s3 = new String(charArray);

// To do 1: print out the string length of s1

System.out.println(s1.length());

// To do 2: loop through characters in s2 with charAt and display reversed

// string

for (int i = s2.length() - 1; i >= 0; --i)

System.out.print(s2.charAt(i));

System.out.println();

// To do 3: compare s2, s3 with compareTo(), print out which string (s2 or s3)

// is

// greater than which string (s2 or s3), or equal, print the result out

if (s2.compareTo(s3) == 0)

System.out.println("They are equal");

else if (s2.compareTo(s3) > 0)

System.out.println("s2 is greater");

else

System.out.println("s3 is greater");

// To do 4: Use the regionMatches to compare s2 and s3 with case sensitivity of

// the first 8 characters.

// and print out the result (match or not) .

if (s2.substring(0, 8).compareTo(s3.substring(0, 8)) == 0)

System.out.println("They matched");

else

System.out.println("They DONT match");

// To do 5: Find the location of the first character 'g' in s1, print it out

int i;

for (i = 0; i < s2.length(); ++i)

if(s2.charAt(i)=='g')

break;

System.out.println("'g' is present at index " + i);

// To do 6: Find the last location of the substring "class" from s2, print it

// out

int index = 0, ans = 0;

String test = s2;

while (index != -1) {

ans = ans + index;

index = test.indexOf("class");

test = test.substring(index + 1, test.length());

}

System.out.println("Last location of class in s2 is: " + (ans + 1));

// To do 7: Extract a substring from index 4 up to, but not including 8 from

// s3, print it out

System.out.println(s3.substring(4, 8));

} // end main

} // end class StringLab9

7 0
3 years ago
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