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Marianna [84]
3 years ago
15

Jose is thinking of a number.

Mathematics
1 answer:
alexira [117]3 years ago
3 0

The number is 66.

Solution:

Let the number be x.

To find the number x using given conditions.

Start with the last condition.

It is less than 7 times 8 + 23 = 7 × 8 + 23 = 79

So, the number is less than 79 which implies x < 79.          

Using condition (4),  

It is greater than 5 times 4 = 5 × 4 = 20

So, the number is greater than 79 which implies x > 20.    

Combining condition (4) and (7), we get 20 < x < 79.

Using condition (3) and (5),

The number is a multiple of 11 and 6.

The number which is multiplied by both 11 and 6 is 66, 132, ...

But here x lies between 20 < x < 79.

So x = 66.

66 is not odd number and the sum of the digits is divisible by 2.

Therefore condition (1) and (2) also satisfied.

Hence the number is 66.

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Tommy has 6 more than 3 times the amount of money in his bank account than Judy. Judy has $7500 more than a number in her accoun
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Answer:

Amount of money Judy has in her account is \$(7500+n).

Amount of money Tommy has in his account is  \$(22506+3n)

Step-by-step explanation:

To find : Amount of money in Judy account and amount of money in Tommy account:

Solution:

Given:

Judy has $7500 more than a number in her account.

Let the number be 'n'.

So we can say that;

Amount of money in Judy account is equal to 7500 plus number.

framing in equation form we get;

Amount of money in Judy account = \$(7500+n)

Hence Amount of money Judy has in her account is \$(7500+n).

Now Given:

Tommy has 6 more than 3 times the amount of money in his bank account than Judy.

So we can say that;

Amount of money in Tommy account is equal to 3 multiplied by Amount of money in Judy account plus 6.

framing in equation form we get;

Amount of money in Tommy account = 3(7500+n)+6 =22500+3n+6=\$(22506+3n)

Hence Amount of money Tommy has in his account is  \$(22506+3n).

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Step-by-step explanation:

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Find the length of the curve. R(t) = cos(8t) i + sin(8t) j + 8 ln cos t k, 0 ≤ t ≤ π/4
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we are given

R(t)=cos(8t)i+sin(8t)j+8ln(cos(t))k

now, we can find x , y and z components

x=cos(8t),y=sin(8t),z=8ln(cos(t))

Arc length calculation:

we can use formula

L=\int\limits^a_b {\sqrt{(x')^2+(y')^2+(z')^2} } \, dt

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now, we can plug these values

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now, we can simplify it

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now, we can solve integral

\int \:8\sec \left(t\right)dt

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now, we can plug bounds

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=8\ln \left(\sqrt{2}+1\right)-0

so,

L=8\ln \left(1+\sqrt{2}\right)..............Answer

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2 years ago
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