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Setler [38]
2 years ago
15

The midpoints of an irregular quadrilateral ABCD are connected to form another quadrilateral inside ABCD. Complete the explanati

on of why the quadrilateral is a parallelogram.​
Mathematics
1 answer:
dem82 [27]2 years ago
4 0

Answer:

Suppose: M, N, P, Q are the midpoints of AB, BC, CD, AD respectively

=> MNPQ is the quadrilateral inside ABCD

connect B to D, ΔABD has : M is the midpoint of AB

                                              Q is the midpoint of AD

=> MQ is the midpoint polygon of ΔABD

=> MQ // BD and MQ = 1/2.BD (1)

ΔBCD has: N is the midpoint of BC

                  P is the midpoint of DC

=> NP is the midpoint polygon of ΔBCD

=> NP // BD and NP = 1/2.BD    (2)

from (1) and (2) => MQ // NP ( //BD)

                            MQ = NP  (=1/2.BD)

=> MNPQ is a parallelogram.​

=>  the quadrilateral inside ABCD is a parallelogram.​

Step-by-step explanation:

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Answer:

The required result is proved with the help of angle bisector theorem.

Step-by-step explanation:

Given △ABD and △CBD, AE and CE are the angle bisectors. we have to prove that \frac{AD}{AB}=\frac{DC}{CB}

Angle bisector theorem states that an angle bisector of an angle of a Δ divides the opposite side in two segments that are proportional to the other two sides of triangle.

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∴ the ratio of the length of side DE to length BE is equal to the ratio of the line segment AD to the line segment AB.

\frac{DE}{EB}=\frac{AD}{AB}   →  (1)

In ΔDCB, CE is the angle bisector

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From equation (1) and (2), we get

\frac{AD}{AB}=\frac{CD}{CB}

Hence Proved.

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