There are three partial products in part a because both values, 273 and 346, have all numerical values, that aren't 0, so they can be multiplied and a value will be added.
There are only 2 partial products in part b because in 306, the tens place is worth 0 and anything times 0 = 0. There will be nothing to add for that value.
I’m sorry I’m not sure but rise before run:)
Answer:
y-10=5(x+2)
Step-by-step explanation:
y-y1=m(x-x1)
y-10=5(x-(-2))
y-10=5(x+2)
