Find the integral of 3/sqrt of 1-4x^2
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Answer:
The viscosity at 140°C is predicted to be 7.2
Step-by-step explanation:
The function that model the relationship between viscosity and temperature = Quadratic model
The general form of a quadratic equation is y = a·x² + b·x + c
Therefore, we have;
When y = 10.8, x = 110, which gives;
10.8 = a·110² + b·110 + c = 12100·a + 110·b + c
10.8 = 12100·a + 110·b + c
When y =8.2, x = 130
8.2 = a· 130² + b· 130 + c = 16900·a + 130·b + c
8.2 = 16900·a + 130·b + c
When y = 160, x = 5.8
5.8 = a·160² + b·160 + c = 25600·a + 160·b + c
5.8 = 25600·a + 160·b + c
The three equations above can be listed as follows;
10.8 = 12100·a + 110·b + c
8.2 = 16900·a + 130·b + c
5.8 = 25600·a + 160·b + c
Solving using matrices gives;
From which we have;
a = 0.001, b = -0.37, c = 39.4
Substituting gives;
y = 0.001·x² - 0.37·x + 39.4
When x = 140
y = 0.962·140² - 0.37·140 + 39.4= 7.2
The viscosity at 140°C = 7.2.