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SVEN [57.7K]
4 years ago
5

Find the integral of 3/sqrt of 1-4x^2

Mathematics
1 answer:
erastovalidia [21]4 years ago
8 0
\int {\frac{3}{\sqrt{1-4x^{2}}}} \, dx
= 3\int {\frac{1}{\sqrt{1-4x^{2}}}} \, dx
= 3\int {\frac{1}{\sqrt{4(\frac{1}{4} - x^{2})}}} \, dx
= \frac{3}{2}\int {\frac{1}{\sqrt{\frac{1}{4} - x^{2}}}}\, dx

= \frac{3}{2}sin^{-1}(2x) + C
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sesenic [268]
178 + 336 = 414 and done
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Rafael can choose plan a or Plan B for his long-distance charges. For each plan, cost (in dollars) depends on minutes used (Per
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Answer:

a. Plan B; $4

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3 years ago
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6 0
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ipn [44]

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Then you factor it 2/3 (9x - 6) 6 (3x - 2) get 6 (3x - 2) / 3

then you divide 6/3 with 2

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subtract 4x from both sides

simplify again

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divide both sides by 2

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Answer:

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