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tiny-mole [99]
3 years ago
11

Ken's landscape gardening business makes odd shapes lawns the include semicircles. Find the length of the edging material needed

to border the lawn design. Use 3.14 for pi. The radius of the flowerbed is 2.5 m.
Mathematics
1 answer:
mihalych1998 [28]3 years ago
4 0

Answer:

L_s=7.85\ m

Step-by-step explanation:

<u>Length Of Semicircles </u>

The length of a circle or radius r is

L=2\pi r

A semicircle has half this length:

L_s=\pi r

The radius of the flowerbed is 2.5 m, thus the length of the edging material needed to border the lawn design is

L_s=\pi (2.5)=(3.14)(2.5)=7.85\ m

\boxed{L_s=7.85\ m}

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General Formulas and Concepts:

<u>Pre-Algebra</u>

Equality Properties

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  • Division Property of Equality
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2 - 0.5n= 3n+16
-----------------------            subtract 2 from both sides
-2                   -2

-0.5n = 3n+14
-----------------------             then subtract -3n from both sides as well
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