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Art [367]
3 years ago
12

What is 5 divided by 25

Mathematics
2 answers:
disa [49]3 years ago
5 0

Answer:

0.2

Step-by-step explanation:

I am Lyosha [343]3 years ago
5 0

Answer: .2

Step-by-step explanation:

If the question was 25 divided by 5 it'll be 5 but because it's 5 divided by 25 the answer came out as a deciamal.

.2 can also mean it is 2/10 or maybe 20%

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Can containers with a capacity of 1 liter have different shapes?
tamaranim1 [39]

yes, I'm pretty shure they do

5 0
3 years ago
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What is the product?<br> (4y - 3)(2x(2)+ 3y-5)
aleksley [76]

Answer:

2 2

4y(2y +3y - 5) - 3(2y + 3y - 5)

3 2 2

=8y + 12y - 20y - 6y - 9y + 15

3 2

=8y + 6y - 29y + 15

Step-by-step explanation:

5 0
3 years ago
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Consider the differential equation:
Wewaii [24]

(a) Take the Laplace transform of both sides:

2y''(t)+ty'(t)-2y(t)=14

\implies 2(s^2Y(s)-sy(0)-y'(0))-(Y(s)+sY'(s))-2Y(s)=\dfrac{14}s

where the transform of ty'(t) comes from

L[ty'(t)]=-(L[y'(t)])'=-(sY(s)-y(0))'=-Y(s)-sY'(s)

This yields the linear ODE,

-sY'(s)+(2s^2-3)Y(s)=\dfrac{14}s

Divides both sides by -s:

Y'(s)+\dfrac{3-2s^2}sY(s)=-\dfrac{14}{s^2}

Find the integrating factor:

\displaystyle\int\frac{3-2s^2}s\,\mathrm ds=3\ln|s|-s^2+C

Multiply both sides of the ODE by e^{3\ln|s|-s^2}=s^3e^{-s^2}:

s^3e^{-s^2}Y'(s)+(3s^2-2s^4)e^{-s^2}Y(s)=-14se^{-s^2}

The left side condenses into the derivative of a product:

\left(s^3e^{-s^2}Y(s)\right)'=-14se^{-s^2}

Integrate both sides and solve for Y(s):

s^3e^{-s^2}Y(s)=7e^{-s^2}+C

Y(s)=\dfrac{7+Ce^{s^2}}{s^3}

(b) Taking the inverse transform of both sides gives

y(t)=\dfrac{7t^2}2+C\,L^{-1}\left[\dfrac{e^{s^2}}{s^3}\right]

I don't know whether the remaining inverse transform can be resolved, but using the principle of superposition, we know that \frac{7t^2}2 is one solution to the original ODE.

y(t)=\dfrac{7t^2}2\implies y'(t)=7t\implies y''(t)=7

Substitute these into the ODE to see everything checks out:

2\cdot7+t\cdot7t-2\cdot\dfrac{7t^2}2=14

5 0
3 years ago
Find the distance between the points (6,5√5) and (4,3√2).<br> 2, 2√2, 2√3
FromTheMoon [43]

Answer:

D=\sqrt{(147-30\sqrt{10}}

Step-by-step explanation:

Here we are required to find the distance between two coordinates. We will use the distance formula to find the distance

The distance formula is given as

D=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

Here we are given two coordinates as

(6,5\sqrt{5} ) , (4,3\sqrt{2} )

Substituting these values in the Distance formula given above we get

D=\sqrt{(6-4)^2+(5\sqrt{5} -3\sqrt{2}) ^2}

D=\sqrt{(2)^2+(5\sqrt{5})^2+(3\sqrt{2})^2-2*5\sqrt{5}*3\sqrt{2}}\\

D=\sqrt{4+125+18-2*15\sqrt{10}}\\D=\sqrt{147-30\sqrt{10}}\\

Hence this is our answer

6 0
3 years ago
Gardeners planted bushes in the city park. They wanted 1/3 of the bushes to be rose bushes and 1/4 of the rose bushes to be pink
den301095 [7]
3/4


your answer is D hope i helped

4 0
3 years ago
Read 2 more answers
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