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Artyom0805 [142]
4 years ago
10

What is the domain of the function f(x) = 3|x + 4| + 1? all real numbers all real numbers less than or equal to −4 all real numb

ers greater than or equal to 1 all real numbers greater than or equal to −4
Mathematics
2 answers:
olganol [36]4 years ago
3 0
All real numbers..................<span />
MrRa [10]4 years ago
3 0

Answer:

The correct option is A.

Step-by-step explanation:

The vertex form of an absolute function is

g(x)=a|x-h|+k

Where, (h,k) is vertex.

Domain is the set of input values.

The given function is

f(x)=3|x+4|+1

It is the vertex from of an absolute function. Here h=-4 and k=1, so the vertex of the function is (-4,1).

These functions are defined for all real values of x. So, the domain of the given absolute function is all real numbers

Therefore the correct option is A.

You might be interested in
Simplify the given expression. (18+ - 8)2​
JulsSmile [24]

Answer:

20

Step-by-step explanation:

Our expression:

2 * (18 + - 8)

Plus then minus (+ -) is the same as just minus ( - )

Some examples:

1 + (+ 1) = 2

1 + (- 1) = 0

1 - (+ 1) = 0

1 - (- 1) = 2

Thus, 18 + - 8 is the same as 18 - 8

2 * (18 + - 8) =

= 2 * (18 - 8) =

= 2* (10) =

= 2 * 10 =

= 20

Answer: 20

6 0
3 years ago
What's the next number? 0 , 1/3 , 1/2 , 3/5 , 2/3​
madam [21]

Answer:

The next number of the series 0, 1/3, 1/2, 3/5, and 2/3 is 5/7

Step-by-step explanation:

The given numbers are;

0, 1/3, 1/2, 3/5, and 2/3

The number sequence is formed adding \dfrac{1}{\left (\dfrac{n^2 + n}{2} \right ) } to each (n - 1)th term to get the nth term number in the sequence, with the first term equal to 0, as follows;

For the 2nd term, the (n - 1)th term is 0, and n = 2, gives;

The

0 +\dfrac{1}{\left (\dfrac{2^2 + 2}{2} \right ) } = 0 + \dfrac{1}{3} = \dfrac{1}{3}

For the 3rd term, the (n - 1)th term is 1/3, and n = 3, gives;

\dfrac{1}{3} +\dfrac{1}{\left (\dfrac{3^2 + 3}{2} \right ) } = \dfrac{1}{3} + \dfrac{1}{6} = \dfrac{1}{2}

For the 4th term, the (n - 1)th term is 1/2, and n = 4, gives;

\dfrac{1}{2} +\dfrac{1}{\left (\dfrac{4^2 + 4}{2} \right ) } = \dfrac{1}{2} + \dfrac{1}{10} = \dfrac{3}{5}

For the 5th term, the (n - 1)th term is 3/5, and n = 5, gives;

\dfrac{3}{5} +\dfrac{1}{\left (\dfrac{5^2 + 5}{2} \right ) } = \dfrac{3}{5} + \dfrac{1}{15} = \dfrac{2}{3}

For the next or 6th term, the (n - 1)th term is 2/3, and n = 6, gives;

\dfrac{2}{3} +\dfrac{1}{\left (\dfrac{6^2 + 6}{2} \right ) } = \dfrac{2}{3} + \dfrac{1}{21} =  \dfrac{15}{21} = \dfrac{5}{7}

The next number of the series 0, 1/3, 1/2, 3/5, and 2/3 = 5/7.

6 0
3 years ago
Someone help plz????
slega [8]

Answer:

the answer is 24.1 MM

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
The distance between (9,10 and (9,3)
spayn [35]
Using the distance formula
d= square root of (x2-x1)^2+(y2-y1)^2

(9-9)^2+(10-3)^2
0^2+7^2
0+49
Square root of 49 is 7
d=7
4 0
4 years ago
PLEASE help. The problem is to find the indicated sum.​
alukav5142 [94]
The indicated sum is 350. The answer is 350 because the E or sigma is making you do (6j+2) ten times. Every time you do 6j+2 you start with j as 1 and add a 1 to j for every time you add. For example, [6(1)+2]+[6(2)+2]+[6(3)+2]...[6(10)+2].

Hope this helps.
8 0
3 years ago
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