Answer:
126
Step-by-step explanation:
The square is 12 m long and the triangle is 11 m long
Make variables for each
L = library books
P = telephone books
T = text books
so.... L+P = 2T
now we have to fill in numbers
The total area of pyramid is 113.569 square units
The equation to find the total area of the pyramid is Total area = base area + lateral area.
<u>Solution:</u>
Given, A pyramid has a regular hexagonal base with side lengths of 4 and a slant height of 6.
<em><u>The total area of pyramid is given by:</u></em>
---- eqn 1
Where,

<em><u>The area of base is given as:</u></em>

Where "l" is the side of hexagon.
Substituting we get,

<em><u>The lateral area is given as:</u></em>

Where,
b: base of the triangle
h: height of the triangle
Substituting we get,

Plugging in the values we found in eqn 1 we get,

A = 113.569 square units
<em><u>Summarizing the results:</u></em>
The total area of pyramid is 113.569 square units approximately
The equation used to find total area of pyramid is Total area = base area + lateral area.