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stira [4]
3 years ago
15

Antonio’s pizza charge $8.00 for a large pizza and $1.50 for each topping zine’s pizzeria charge $10.00 for a large pizza and $1

for each topping write and solve a system of equations to determine the number of topping for which the pizzas would cost the same what is what cost.
Mathematics
1 answer:
hichkok12 [17]3 years ago
5 0
In this problem you would set these two equations equal to each other.
$8+ $1.50x = $10+ $1x 
After this you would simplify the equation to isolate x (being the number of toppings you put on the pizzas) 

$8+ 1.50x =$10+ 1x
-8              -8
----------------------------
$1.50x = $2 + $1x
-1x             -1x
--------------------------- 
$.50x/.50 = $2/.50
_______________
x= 4 toppings and the pizzas would equal $14 total 

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Hurry please thank u if u answer​
AlekseyPX

Answer:

92

Step-by-step explanation:

<C = 180 - 140 = 40 deg

180 = 40 + 2x + (x+2)....... x= 46

<B = 2x = 2*46 = 92 deg ans

6 0
3 years ago
What is the surface area of the prism?
cestrela7 [59]

Step 1: Find the area of the bases (triangles)

A = 1/2 * base * height

A = 1/2 * 16 * 6

A = 48

48 + 48 = 96

Area of the triangles = 96 cm^2

Step 2: Find the area of the sides (rectangles)

A = base * height

A1 = 16 * 12

A1 = 192

A2 = 10 * 12

A2 = 120

120 + 120 = 240

240 + 192 = 432 cm^2

Step 2: Add the areas together

96 + 432

528 cm^2

Hope this helps!! :)

5 0
3 years ago
27. Dylan bought 3 identical shirts online for a total cost of $71.83 including a flat rate of $7.99 for shipping. Write
Sav [38]

Answer:

71.83

Step-by-step explanation:

3 0
2 years ago
It is estimated that 0.54 percent of the callers to the Customer Service department of Dell Inc. will receive a busy signal. Wha
stira [4]

Using the binomial distribution, it is found that there is a 0.8295 = 82.95% probability that at least 5 received a busy signal.

<h3>What is the binomial distribution formula?</h3>

The formula is:

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

C_{n,x} = \frac{n!}{x!(n-x)!}

The parameters are:

  • x is the number of successes.
  • n is the number of trials.
  • p is the probability of a success on a single trial.

In this problem:

  • 0.54% of the calls receive a busy signal, hence  p = 0.0054.
  • A sample of 1300 callers is taken, hence n = 1300.

The probability that at least 5 received a busy signal is given by:

P(X \geq 5) = 1 - P(X < 5)

In which:

P(X < 5) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4).

Then:

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{1300,0}.(0.0054)^{0}.(0.9946)^{1300} = 0.0009

P(X = 1) = C_{1300,1}.(0.0054)^{1}.(0.9946)^{1299} = 0.0062

P(X = 2) = C_{1300,2}.(0.0054)^{2}.(0.9946)^{1298} = 0.0218

P(X = 3) = C_{1300,3}.(0.0054)^{3}.(0.9946)^{1297} = 0.0513

P(X = 4) = C_{1300,4}.(0.0054)^{4}.(0.9946)^{1296} = 0.0903

Then:

P(X < 5) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) = 0.0009 + 0.0062 + 0.0218 + 0.0513 + 0.0903 = 0.1705.

P(X \geq 5) = 1 - P(X < 5) = 1 - 0.1705 = 0.8295

0.8295 = 82.95% probability that at least 5 received a busy signal.

More can be learned about the binomial distribution at brainly.com/question/24863377

#SPJ1

6 0
2 years ago
- Write a recursive formula to represent the sequence below.<br> (3,7, 11, 15, 19,23,27,31,35, ...)
NemiM [27]

<em><u>The recursive formula to find nth term of sequence is:</u></em>

a_n = 4n - 1 \text{ where } n \geq 1 and n  = 1, 2, 3, ....

<em><u>Solution:</u></em>

Given a sequence is:

3, 7, 11, 15, 19, 23, 27, 31, 35

<em><u>Let us find the difference between terms</u></em>

7 - 3 = 4

11 - 7 = 4

15 - 11 = 4

19 - 15 = 4

23 - 19 = 4

27 - 23 = 4

31 - 27 = 4

35 - 31 = 4

Thus the difference between terms is constant

Thus the given sequence is arithmetic sequence

An arithmetic sequence is a sequence of numbers such that the difference of any two successive members of the sequence is a constant

<em><u>The nth term of arithmetic sequence is given by:</u></em>

a_n =a_1+(n-1)d

a_n = the nᵗʰ term in the sequence

a_1 = the first term in the sequence

d = the common difference between terms

Here in the given sequence

d = 4

a_1=3

Substitute in above formula,

a_n = 3 + (n-1)(4)\\\\a_n = 3 + 4n - 4\\\\a_n = 4n - 1

<em><u>Thus the recursive formula to find nth term of sequence is:</u></em>

a_n = 4n - 1 \text{ where } n \geq 1 and n = 1, 2, 3, ......

8 0
3 years ago
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