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nataly862011 [7]
3 years ago
7

In a 45-45-90 triangle, what is the length of the hypotenuse when the length of one of the legs is 5 in.?

Mathematics
2 answers:
Contact [7]3 years ago
5 0
Hello!

since this is a 45-45-90 degree triangle the hypotenuse is a\sqrt{2} where a is one of the legs

So the answer is 5\sqrt{2}

Hope this helps!
Ainat [17]3 years ago
3 0
The proportions in a 45-45-90 triangle are
1 : 1 : square root 2.

Finding the length of the hypotenuse can be done with the following formula:
length of a leg × square root of 2

Therefore in a 45-45-90 triangle with legs with a length of 5 inches, the hypotenuse is
5 \times \sqrt{2} = 5 \sqrt{2} \: in.
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The factored expression is:

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To factor the expression:

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The expression is:

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The gcf of the entire expression is the multiplication of the gcfs of the numeric and of the symbolic coefficients, so it is 3y.

Now, to factore the expression:

3x^3y + 12xy - 9x^2y - 36y = 3y(\frac{3x^3y}{3y} + \frac{12xy}{3y} - \frac{9x^2y}{3y} - \frac{36y}{3y}) = 3y(x^3 + 4x - 3x^2 - 12)

The factored expression is:

3y(x^3 + 4x - 3x^2 - 12)

A similar problem is given at brainly.com/question/20691631

8 0
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