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babunello [35]
3 years ago
10

HELP ASAP.

Mathematics
2 answers:
OLEGan [10]3 years ago
8 0

Answer:

C

Step-by-step explanation:

ratio of red : blue = 4 : 6 = 2 : 3 ← in simplest form

eduard3 years ago
4 0

Answer:  4:6

Step-by-step explanation:

It is telling you FROM red marbles TO blue marbles so it it 4:6. If it was FROM blue marbles TO red marbles then it will be 6:4.

PLEASE MARK BRAINLIEST!!!!

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Please help!! thank you
Ganezh [65]

I got .00390625 for the answer

8 0
3 years ago
Read 2 more answers
A ladder is leaning against the house. The base of the ladder is 9 feet from the base of the house. The ladder is 20 feet long.
zvonat [6]

Answer:

17.86057

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
Two runners start 30kilometer apart and run toward each other. they meet after 3hours. One Runner runs 2 kilometers per hour fas
joja [24]

Answer:

4 km per hour and 6 km per hour.

Step-by-step explanation:

The combined running rate  = 30/3 = 10 km/h.

If one runner's speed = x then the other one's speed is x+2 km/h.

So x + x + 2 = 10

2x = 8

x = 4

So one runs at 4 km/h and the other at 6 km/h.

3 0
3 years ago
What is the difference between an irrational number and an integer? (PLZ HELP ME ANSWER ASAP!!!! All help is appreciated! :D)
enot [183]
So, first off it would help if you could define the terms irrational number and integer. Well, an irrational number is basically any real number that can't be expressed as a ratio of integers. They also cannot be represented by terminating or continuing decimals. And an integer is pretty much any number that cannot be written as a fraction or decimal, such as -2, 13, 257. It is not 2 and 1/2, or 4.75. Those would not be integers. Do you think you can figure out the difference?

8 0
3 years ago
Find the directional derivative of the function at the given point in the direction of the vector v. f(x, y, z) = xyz , (3, 3, 9
Anna [14]

The derivative of f(x,y,z) in the direction of a vector \mathbf u is

\nabla_{\mathbf u}f=\nabla f\cdot\dfrac{\mathbf u}{\|\mathbf u\|}

With f(x,y,z)=xyz, we get

\nabla f=(yz,xz,xy)

and \mathbf u=(-1,-2,2),

\|\mathbf u\|=\sqrt{(-1)^2+(-2)^2+2^2}=3

Then

\nabla_{(-1,-2,2)}f(3,3,9)=(27,27,9)\cdot\dfrac{(-1,-2,2)}3=-21

8 0
3 years ago
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