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2 years ago

A construction company purchased 5 tons of cement. The price was $47 per ton. What was the total price of the cement?

Mathematics

1 answer:

klasskru [66]2 years ago

3 0

Answer:

$235

Step-by-step explanation:

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Do you guys know what 4m - 2m + 3

lyudmila [28]

Answer:

2m + 3 I think.

Step-by-step explanation:

4m - 2m = 2m. So just put that in the equation now and poof. 2m + 3

4 0

1 year ago

Esther. Vida and Clair were asked to consider two different cash flows: GH¢1000 that theycould receive today and GH¢3000 that wo

xxMikexx [17]

Answer:

The right choice is Esther's

Step-by-step explanation:

Present worth of GH¢ after 3 years is better as its present really worth may be very high than GH¢ a thousand of today. Here fee of interest is not given to compare however GH¢ 3000 after three years will be equivalent to present well worth GH¢ 1000 if charge of interest >44.5% which may be very very excessive. Thus charge of interest > 44.5% Then GH¢ 3000 payable after 3 years could be equivalent to GH¢ 1000 Hence vide has made the proper preference. If interest price >44.5%.

Then Esther's preference will he right. (thinking about time value of money).

6 0

2 years ago

Max says that the elapsed time from 11:55 AM to 1:01 PM is more than an hour and a half. Is he correct ? Explain.

kati45 [8]

He is wrong because 12:55 is one hr and you still need to get to 1:25 but he only got to 1:01 so he did not get the correct answer

5 0

3 years ago

30 years ago zoe was 2/3 as old as luke, 18 years ago zoe was 5/6 as old as luke how old are they now

barxatty [35]

Based on the mathematical statements, Zoe is 56 years old and Luke is 66 years old, now

<h3>How to determine how old they are now?</h3>

From the question, we have the following statements that can be used in our computation:

<u>30 years ago</u>

Zoe was 2/3 as old as Luke

<u>18 years ago</u>

Zoe was 5/6 as old as Luke

Let their present ages be represented as

Zoe = x

Luke = y

So, we have the following representations

<u>30 years ago</u>

Zoe was 2/3 as old as Luke

x - 36 = 2/3(y - 36)

<u>18 years ago</u>

Zoe was 5/6 as old as Luke

x - 18 = 5/6(y - 18)

So, we have the following system of equations

x - 36 = 2/3(y - 36)

x - 18 = 5/6(y - 18)

Make x the subject in x - 18 = 5/6(y - 18)

x = 5/6(y - 18) + 16

Substitute x = 5/6(y - 18) + 16 in x - 36 = 2/3(y - 36)

5/6(y - 18) + 16 - 36 = 2/3(y - 36)

Open the brackets

5/6y - 15 + 16 - 36 = 2/3y - 24

Evaluate the like terms

5/6y - 35 = 2/3y - 24

Multiply through by 6

5y - 210 = 4y - 144

Evaluate the like terms

y = 66

Substitute y = 66 in x = 5/6(y - 18) + 16

x = 5/6(66 - 18) + 16

Evaluate

x = 56

Recall that

Zoe = x

Luke = y

So, we have

Zoe = x = 56

Luke = y = 66

Hence, they are 56 and 66 years, now