Length of deck is 40 feet
<h3><u><em>Solution:</em></u></h3>
Sam wants the deck to have an overall perimeter of 60 feet
Perimeter of rectangular deck = 60 feet
Let "L" be the length of rectangle and "W" be the width of rectangle
Given that plans for a rectangular deck call for the width to be 10 feet less than the length
Width = length - 10
W = L - 10 ------ eqn 1
<em><u>The perimeter of rectangle is given as:</u></em>
perimeter of rectangle = 2(length + width)
Substituting the known values we get,
60 = 2(L + L - 10)
60 = 2(2L - 10)
60 = 4L - 20
80 = 4L
L = 20
Thus the length of deck is 20 feet
The dimensions of the carton are:
10 x 10 x 10 [inch OR unit cubes - it's the same since cubes' dimensions are 1 x 1 x 1 inch)
I attach the explanation below.
With what????????????????????
Answer:
164 Cm^3
Step-by-step explanation:
Solution
V=
3
3
2
a
2
h
=
3
3
2
3
2
7
≈
163.6788
The equation is:
h ( t ) = - 16 t² + 60 t + 3
The toy rocket will reach the ground when: h ( t ) = 0
- 16 t² + 60 t + 3 = 0

t 1 = - 0.05
t 2 = 3.8
Answer:
C ) 3.80 s