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STatiana [176]
3 years ago
15

I need help in number 13

Mathematics
2 answers:
Gekata [30.6K]3 years ago
8 0

Answer:

\huge\boxed{-0.602}

Step-by-step explanation:

\displaystyle log (\frac{1}{4} )\\\\We \ know \ that :\\\\log (\frac{x}{y} ) = log x - log y\\\\Applying \ the \ above \ rule\\\\= log 1 - log 4\\\\Given \ that \ log \ 1 = 0 , log \ 4 = 0.602\\\\= 0 - 0.602\\\\= -0.602\\\\\rule[225]{225}{2}

Hope this helped!

<h3>~AH1807</h3>
julia-pushkina [17]3 years ago
6 0

13.

log ( 1/4) = - log ( 4 ) = - 0.602

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A rectangle measures 12 cm by 10.5 cm. what is the greatest possible error for each measurement? Please and thankyou:)
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The answer is going to be 0.5 hopes this helps.
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Caseys took 25 tests in 135 days at this rate in how many days will she take another 10 test
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The half-life of a radioactive substance is the time it takes for a quantity of the substance to decay to half of the initial am
posledela

Step-by-step walkthrough:

a.

Well a standard half-life equation looks like this.

N = N_0 * (\frac{1}{2})^{t/p

N_0 is the starting amount of parent element.

N is the end amount of parent element

t is the time elapsed

p is a half-life decay period

We know that the starting amount is 74g, and the period for a half-life is 2.8 days.

Therefore you can create a function based off of the original equation, just sub in the values you already know.

N(t) = 74g * (\frac{1}{2})^{t/2.8days

b.

This is easy now that we have already made the function. Here we just reuse it, but plug in 2.8 days.

N(t) = 74g * (\frac{1}{2})^{t/2.8days} = N(2.8days) = 74g * (\frac{1}{2})^{2.8days/2.8days}\\= 74g * \frac{1}{2}  =  37g

c.

Now we just gotta do some algebra. Use the original function but this time, replace N(t) with 10g and solve algebraically.

10g = 74g * (\frac{1}{2})^{t/2.8days}\\\\\frac{10g}{74g} = (\frac{1}{2})^{t/2.8days}

Take the log of both sides.

log(\frac{5}{37}) = log((\frac{1}{2})^{t/2.8days})

Use the exponent rule for log laws that, log(b^x) = x*log(b)

log(\frac{5}{37}) = \frac{t}{2.8days} * log(\frac{1}{2})

\frac{log(\frac{5}{37})}{log(\frac{1}{2})}  = \frac{t}{2.8days}

2.8 * \frac{log(\frac{5}{37})}{log(\frac{1}{2})}  = t

slap that in your calculator and you get

t = 8.1 days

7 0
2 years ago
Are they similar or no? Please help.
Troyanec [42]

Answer:

they are not similar because the ratio between its sides are different

hope it helps! :D

8 0
3 years ago
Read 2 more answers
If the area of the triangle is 48 square units, what is the total area of sections 1 and 2?
MariettaO [177]

Answer:

48 square unit

Step-by-step explanation:

For a rectangle, area is given by

A=bh

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Then bh=2*48=96 square units

The overall area is 96 square units.

The area for 1&2 combined will be given by deducting the area of triangle from the overall area

Area is 96-48=48 square units

6 0
3 years ago
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