It has a y intercept of 1 rather than 0.
It is shifted one unit up.
7.
(2b^2+7b^2+b)+(2b^2-4b-12)
(9b^2+b)+(2b^2-4b-12)
9b^2+b+2b^2-4b-12
11b^2+b-4b-12
11b^2-3b-12
8.
(7g^3+4g-1)+(2g^2-6g+2)
7g^3+4g-1+2g^2-6g+2
7g^3-2g-1+2g^2+2
7g^3-2g+1+2g^2
7g^3+2g^2-2g+1
Hope this helps!
Let x be the number of people that can be seated.
The value of x is some number 0 or greater, such that this number is a whole number (we can't have half a person). This means that

which is the same as saying

The instructions state that we can seat up to 1200 people. This is the max capacity. We can't go over this amount. So we will also have

indicating that x can be less than 1200 or equal to 1200.
So putting the two inequalities together, we get

Note: if you haven't learned about compound inequalities yet, then the teacher may only want

as the answer.
Answer:
Step-by-step explanation:
Below is the pic of how this would be set up in order to determine what it is you are looking for. The angle is set in QI, and since csc A is the reciprocal of sin, the ratio is hypotenuse over side opposite. Solve for the missing side using Pythagorean's Theorem:
and
1369 = 144 + b² and
1225 = b² so
b = 35
The sec ratio is the reciprocal of cos, so if cos is adjacent over hypotenuse, the sec is hypotenuse over adjacent, which is 37/35
I think it is scend choose