If an infant drink 38 ounces of milk a day. what is the approximate amount he will drink in quarts

21. Given: f(x) = (x - 2)2 + 4 g(x) = (x – 5)2 + 4 When compared to the graph of

VARVARA [1.3K]

2 your welcome d d d d d d. d d d d s s s s

7 0

3 years ago

Determine if x-6 is a zero and find the quotiant and the remainder

sergiy2304 [10]

Answer:

○ A. No, x = -6 is not a zero of the polynomial.

The quotient is x - 29, and the remainder is 234.

Step-by-step explanation:

[x - 3][x - 20] >> Factored Form

Obviously, this is not a zero. Now, to get the remainder, we have to plug in the vertical line of x = -6 into its conjugate, meaning an expression with opposite signs, which is x + 6. This is the expression we divide the dividend by, so you will have this:

\frac{{x}^{2} - 23x - 60}{x + 6}

Since the divisor is in the form of x - c, using Synthetic Division, we get this:

x - 29 + \frac{234}{x + 6}

You see? You have x - 29 in the quotient, and you have 234 as the numerator remainder.

I am joyous to assist you anytime.

3 0

3 years ago

You earn $35 for washing 7 cars. How much do you earn for washing 4 cars?

Tanzania [10]

35/7 = 5$ per car so 4x5= 20$

6 0

3 years ago

Read 2 more answers

Listed below are the number of years it took for a random sample of college students to earn bachelor's degrees (based on data f

schepotkina [342]

Answer:

a) Mean = 6.5, sample standard deviation = 3.50

b) Standard error = 0.7826

c) Point estimate = 6.5

d) Confidence interval: (5.1469 ,7.8531)

Step-by-step explanation:

We are given the following data set for students to earn bachelor's degrees.

4, 4, 4, 4, 4, 4, 4.5, 4.5, 4.5, 4.5, 4.5, 4.5, 6, 6, 8, 9, 9, 13, 13, 15

a) Formula:

$\text{Standard Deviation} = \sqrt{\displaystyle\frac{\sum (x_i -\bar{x})^2}{n-1}}$

where $x_i$ are data points, $\bar{x}$ is the mean and n is the number of observations.

$Mean = \displaystyle\frac{\text{Sum of all observations}}{\text{Total number of observation}}$

$Mean =\displaystyle\frac{130}{20} = 6.5$

Sum of squares of differences = 6.25 + 6.25 + 6.25 + 6.25 + 6.25 + 6.25 + 4 + 4 + 4 + 4 + 4 + 4 + 0.25 + 0.25 + 2.25 + 6.25 + 6.25 + 42.25 + 42.25 + 72.25 = 233.5

$S.D = \sqrt{\frac{233.5}{19}} = 3.50$

b) Standard Error

$= \displaystyle\frac{s}{\sqrt{n}} = \frac{3.50}{\sqrt{20}} = 0.7826$

c) Point estimate for the mean time required for all college is given by the sample mean.

$\bar{x} = 6.5$

d) 90% Confidence interval:

$\bar{x} \pm t_{critical}\displaystyle\frac{s}{\sqrt{n}}$

Putting the values, we get,

$t_{critical}\text{ at degree of freedom 19 and}~\alpha_{0.10} = \pm 1.729$

$6.5 \pm 1.729(\frac{3.50}{\sqrt{20}} ) = 6.5 \pm 1.3531 = (5.1469 ,7.8531)$

e) No, the confidence interval does not contain the value of 4 years. Thus, confidence interval is not a good estimator as most of the value in the sample is of 4 years. Most of the sample does not lie in the given confidence interval.

5 0

4 years ago

Which best describes the equation that the graph represents?

andreev551 [17]

Answer:

y= $\frac{9}{5}$ x