Full Question
A 10 kilogram object suspended from the end of a vertically hanging spring stretches the spring 9.8 centimeters. At time t = 0, the resulting mass—spring system is disturbed from its rest state by the force F (t) = 20 cos(8t). The force F (t) is expressed in Newtons and is positive in the downward direction, and time is measured in seconds.
Determine the spring constant k.
Answer:
Spring Constant = 1000Nm^-1
Step-by-step explanation:
Given
Mass = 10kg
Spring Extension = 9.8cm
Spring Constant K = Force/Extension
Force = Mass * Acceleration
Force = 10 * 9.8 = 9.8N
Spring Extension = 9.8 cm = 9.8 /100 = 0.098 m
Spring constant = 98 / 0.098
Spring Constant = 1000Nm^-1
4x + 3y = 54 (1)
3x + 9y = 108 (2)
Multiply (1) by (-3)
-12x - 9y = -162
3x + 9y = 108
---------------------add
-9x = -54
x = 6
plug x = 6 into (1) to find y
4(6) + 3y = 54
24 + 3y = 54
3y = 30
y = 10
Answer
(6 , 10)
Hope it helps.
Answer:
The 4 t h term is f(4) = 143
Step-by-step explanation:
<em>Explanation</em>:-
Given function f(1) = -4
Given 'nth' term is f(n) = -3f(n-1) +5
Put n =2 <em> f(2) = -3 f(2-1) +5</em>
= -3 f(1) +5
= -3 (-4) +5
= 12 +5
f(2) = 17
put n= 3
f(n) = -3f(n-1) +5
<em> f(3) = -3 f(3-1) +5</em>
= -3f(2) +5
= -3(17) +5
= -51+5
f(3) = -46
Put n=4
f(n) = -3f(n-1) +5
<em> f(4) = -3f(4-1) +5</em>
<em> f(4) = -3f(3)+5</em>
f(4) = -3(-46)+5
f(4) = 138 +5
f(4) = 143
<u><em>Final answer</em></u>:-
<em>The 4 t h term is f(4) = 143</em>
Answer:
Yes because the 1st and 3rd one are functions
Step-by-step explanation:
Answer:
Step-by-step explanation:
orginal :$240
new/sale: $180
Percentage of Change:
(V2−V1)|V1|×100
=(180−240)|240|×100
=−60240×100
=−0.25×100
=−25%change
=25%decrease
