Mike age is 3 less then twice the age of his brother nuke.
M = Mike's age now
N = Nuke's age now
M = 2N - 3
Ten years ago, four times nuke's age was one more mike's age.
M-10 = Mike's age 10 years ago
N-10 = Muke's age 10 years ago
4(N - 10) = 1 + M -10
what are their present ages
find M and N
substitute M = 2N - 3 into 4(N - 10) = 1 + M -10:
4(N - 10) = 1 + [2N - 3] - 10
4N - 40 = 2N - 12
2N = 28
N = 14
M = 2(14) - 3 = 28 - 3 = 25
Mike is 25 and Nuke is 14.
check:
4(14 - 10) = 4(4) = 16 = 26 -10 = 1 + 25 - 10
Use a system of equations.
(x=# of small dogs, y=# of big dogs)
x+y=9 (times by -5) -5x-5y=-45
5x+8y=51
Then add the equations together and the x's cancel.
3y=6
y=2
So he walked 2 big dogs and 7 little dogs.
1 yd is equivalent to 3 ft, so 7 times 3 is 21. 21 is greater than 20, so your answer is 7 yd.
Answer:
the answer is 3.6km is bigger then 3,600 m
To put a fraction into simplest form, you need to divide both the numerator and the denominator by the GCF of both of these numbers.
35 and 42 have a GCF of 7.
So, if we divide
35/7=5
42/7=6
Therefore, 35/42 in simplest form is 5/6
