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gogolik [260]
3 years ago
14

50 points!!! ANSWER ASAP WHAT GOES IN THE BOX?

Mathematics
2 answers:
Ket [755]3 years ago
5 0

Answer:

9

Step-by-step explanation:

Since it is a multiplication problem you would add all of the exponents up.

2^2 * 2^3 * 2^4

2^(2+3+4)

julsineya [31]3 years ago
4 0

Answer:

2⁹

Step-by-step explanation:

Using the rule of Indices:

aⁿ x aˣ = aⁿ⁺ˣ

Hence: 2²⁺³⁺⁴

= 2⁹

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4 0
3 years ago
For which values of a the system has at least one solution: x≤7 x≥a urgent pls help now
allochka39001 [22]

Answer:

We have the system:

x ≤ 7

x ≥ a

Now we want to find the possible values of a such that the system has, at least, one solution.

First, we should look at the value of a where the system has only one solution:

We can write the 2 sets as:

a ≤ x

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So, writing both together:

a ≤ x ≤ 7

if a is larger than 7, we do not have solutions.

then a = 7 gives:

7 ≤ x ≤ 7

Here the only solution is 7.

Now, if a is smaller than 7, for example 5, we have:

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Now x can take different values, so we have a lot of solutions.

Then the restrictions for a, such that the system has at least one solution, is:

a ≤ 7.

6 0
4 years ago
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