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Readme [11.4K]
3 years ago
5

What's the answer? (please help soon!)

Mathematics
1 answer:
nignag [31]3 years ago
3 0
Absolute value make it positive

15-|-5|=15-5=10

|-4|+6=4+6=10

-|7+3|=-|10|=-(10)=-10

|-10|=10

so it is -|7+3| that doesn't belong
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Simplify this expression
luda_lava [24]

7 and 21 can cancel leaving a 3 on the bottom. one m can cancel from the bottom and the top so that leaves you with m^3 n^4/3

4 0
3 years ago
6+12 ÷3x2-3x4<br><br><br> please solve step-by-step begginers
kari74 [83]

Answer:

The answer is 2

Step-by-step explanation:

Hope this helps.

8 0
2 years ago
Read 2 more answers
An indoor track is made up of a rectangular region with two semi-circles at the ends. The distance around the track is 400 meter
dybincka [34]

Answer:

width of rectangle = 2R = (200/π) = 400/π meters

length of rectangle = 400 - π(200/π) = 400 - 200 = 200 meters

Step-by-step explanation:

The distance around the track (400 m) has two parts:  one is the circumference of the circle and the other is twice the length of the rectangle.

Let L represent the length of the rectangle, and R the radius of one of the circular ends.  Then the length of the track (the distance around it) is:

Total = circumference of the circle + twice the length of the rectangle, or

         =                    2πR                    + 2L    = 400 (meters)  

This equation is a 'constraint.'  It simplifies to πR + L = 400.  This equation can be solved for R if we wish to find L first, or for L if we wish to find R first.  Solving for L, we get L = 400 - πR.

We wish to maximize the area of the rectangular region.  That area is represented by A = L·W, which is equivalent here to A = L·2R = 2RL.  We are to maximize this area by finding the correct R and L values.

We have already solved the constraint equation for L:  L = 400 - πR.  We can substitute this 400 - πR for L in

the area formula given above:    A = L·2R = 2RL = 2R)(400 - πR).  This product has the form of a quadratic:  A = 800R - 2πR².  Because the coefficient of R² is negative, the graph of this parabola opens down.  We need to find the vertex of this parabola to obtain the value of R that maximizes the area of the rectangle:        

                                                                   -b ± √(b² - 4ac)

Using the quadratic formula, we get R = ------------------------

                                                                            2a

                                                   -800 ± √(6400 - 4(0))           -1600

or, in this particular case, R = ------------------------------------- = ---------------

                                                        2(-2π)

            -800

or R = ----------- = 200/π

            -4π

and so L = 400 - πR (see work done above)

These are the dimensions that result in max area of the rectangle:

width of rectangle = 2R = (200/π) = 400/π meters

length of rectangle = 400 - π(200/π) = 400 - 200 = 200 meters

5 0
2 years ago
Can someone help me with this ?
Nastasia [14]
All the questions??????

3 0
3 years ago
I really need some math help. How do I do this?
lukranit [14]

First, find the value of <em>x</em>. Then, use the measures of the arcs to find the value of <em>w</em>.

When two chords intersect, the measure of the internal angle is equal to the average of the arcs that it encloses:

c=\frac{1}{2}(a+b)

Since the angle of 70° encloses arcs of 60° and x°, then:

70=\frac{1}{2}(60+x)

Solve for <em>x:</em>

\begin{gathered} x=2\times70-60 \\ =140-60 \\ =80 \end{gathered}

The sum of the measures of the arcs of a circle must be equal to 360°. Then:

w+x+79+60=360

Substitute <em>x=80</em> and solve for <em>w:</em>

\begin{gathered} \Rightarrow w+80+79+60=360 \\ \Rightarrow w+219=360 \\ \Rightarrow w=360-219 \\ \Rightarrow w=141 \end{gathered}

Therefore, the value of w is:

141^{\circ}

5 0
11 months ago
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