we know that
To find how long are 
sections placed end to end
Multiply the number of sections by the length of one section
so
therefore
<u>the answer is</u>
The kite is approximately 78.80 feet off of the ground.
Explanation: If we assume that the string his held taut without any swag, we can use a right triangle to solve for the height of the kite. sin
θ
=
o
p
p
h
y
p
sin
52
o
=
h
100
f
t
100
sin
52
o
=
h
100
(
0.7880
)
=
h
78.80
f
t
=
h
Answer:
5x -12 = 3x +8 (set the two = each other because they are the same length)
2x- 12= 8 (subtract 3x from both sides)
2x = 20 (add 12 to both sides)
x=10 (what x= for both expressions)
5(10) -12 (plug it into the first one to see what the length is and to see they're =
50 - 12 ( I already multiplied, now subtract)
38 (what the length of TR is)
3(10) +8 (plug it in again but into the other expression)
30+8 (multiply and add)
38 (the two have the same answer, so the x-value is correct.)
38+38= 76 (add the lengths of RS and TR and you get the length of TS)
Step-by-step explanation:
I hope this helps :)
Answer:
the volume of the solid generated by revolving the region bounded by the graphs of the equations about the x-axis is;
![\frac{\pi }{2} [e^2 - 1 ]](https://tex.z-dn.net/?f=%5Cfrac%7B%5Cpi%20%7D%7B2%7D%20%20%5Be%5E2%20-%201%20%5D)
or 10.036
Step-by-step explanation:
Given the data in the question;
y = 
, y = 0, x = 1, x = 2.
Now, using the integration capabilities of a graphing utility
y = 
, y = 0
Volume = 
Volume = 
Volume = 
Volume = 
Volume = ![\frac{\pi }{e^2} [\frac{e^{2x}}{2}]^2_1](https://tex.z-dn.net/?f=%5Cfrac%7B%5Cpi%20%7D%7Be%5E2%7D%20%20%5B%5Cfrac%7Be%5E%7B2x%7D%7D%7B2%7D%5D%5E2_1)
Volume = ![\frac{\pi }{2e^2} [e^4 - e^2 ]](https://tex.z-dn.net/?f=%5Cfrac%7B%5Cpi%20%7D%7B2e%5E2%7D%20%20%5Be%5E4%20-%20e%5E2%20%5D)
Volume = or 10.036
Therefore, the volume of the solid generated by revolving the region bounded by the graphs of the equations about the x-axis is;
or 10.036
