Answer:20p+16
Step-by-step explanation:
Combine like terms
4(7p+4-2p)
4(5p+4)
Distribute
4(5p+4)
20p+16
Answer:
The second time when Luiza reaches a height of 1.2 m = 2 08 s
Step-by-step explanation:
Complete Question
Luiza is jumping on a trampoline. Ht models her distance above the ground (in m) t seconds after she starts jumping. Here, the angle is entered in radians.
H(t) = -0.6 cos (2pi/2.5)t + 1.5.
What is the second time when Luiza reaches a height of 1.2 m? Round your final answer to the nearest hundredth of a second.
Solution
Luiza is jumping on trampolines and her height above the levelled ground at any time, t, is given as
H(t) = -0.6cos(2π/2.5)t + 1.5
What is t when H = 1.2 m
1.2 = -0.6cos(2π/2.5)t + 1.5
0.6cos(2π/2.5)t = 1.2 - 1.5 = -0.3
Cos (2π/2.5)t = (0.3/0.6) = 0.5
Note that in radians,
Cos (π/3) = 0.5
This is the first time, the second time that cos θ = 0.5 is in the fourth quadrant,
Cos (5π/3) = 0.5
So,
Cos (2π/2.5)t = Cos (5π/3)
(2π/2.5)t = (5π/3)
(2/2.5) × t = (5/3)
t = (5/3) × (2.5/2) = 2.0833333 = 2.08 s to the neareast hundredth of a second.
Hope this Helps!!!
124 - 78 = 46.....Harrison used 46 more blocks then Greyson
I am not going to tell you the answer but i can tell you how to find it out. First you have to put 19/38 on a paper. Then multipy the numarator and denomanator by the same number on the top and bottom which is called a whole number. 19/38 times 2/2 or 3/3 or 4/4 or anything. Your answer is equivalent to 19/38
Answer:
i don't have the table so no one can answer
Step-by-step explanation:
