we are given

we can check each options
option-A:
-1,1
we can plug x=-1 and x=1 and check whethet f(x)=0
At x=-1:


At x=1:


so, this is TRUE
option-B:
0,1
we can plug x=0 and x=1 and check whethet f(x)=0
At x=0:


At x=1:


so, this is FALSE
option-C:
-2,-1
we can plug x=-2 and x=-1 and check whethet f(x)=0
At x=-2:


At x=-1:


so, this is FALSE
option-D:
-1,0
we can plug x=-1 and x=0 and check whethet f(x)=0
At x=-1:


At x=0:


so, this is FALSE
Answer:
Add: $100
Take Out: $25
Total: $835.50
Step-by-step explanation:
A deposit is an amount that is put into the account, by the owner or by someone else.
A withdrawal is an amount that is taken out of the account.
The overall ending balance shows the total amount in the account at the end of the month.
Answer:
you got this your smart
Step-by-step explanation:
Answer:
<em>Answer is</em><em> </em><em>given</em><em> </em><em>below with explanations</em><em>. </em>
Step-by-step explanation:

<em>HAVE A NICE DAY</em><em>!</em>
<em>THANKS FOR GIVING ME THE OPPORTUNITY</em><em> </em><em>TO ANSWER YOUR QUESTION</em><em>. </em>
Answer:
50888888888888888888+++++