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2 years ago

Match each set of values to the correct median

Mathematics

1 answer:

Kobotan [32]2 years ago

5 0

Answer:

Please, where are the values ?

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Which values of X are solutions to the inequality

Natasha_Volkova [10]

Answer:

The third answer choice

Step-by-step explanation:

-3(x+2) < 5x+10

-3x-6 < 5x+10

-3x-5x < 10+16

-8x < 16

x < -2

6 0

2 years ago

you are playing the integer game with your friends. you have drawn a -2 and -3 from the deck. when you add the numbers on these

ahrayia [7]

Answer:

Step-by-step explanation:

Njkkmknb

4 0

2 years ago

For the following telescoping series, find a formula for the nth term of the sequence of partial sums

gtnhenbr [62]

I'm guessing the sum is supposed to be

$\displaystyle\sum_{k=1}^\infty\frac{10}{(5k-1)(5k+4)}$

Split the summand into partial fractions:

$\dfrac1{(5k-1)(5k+4)}=\dfrac a{5k-1}+\dfrac b{5k+4}$

$1=a(5k+4)+b(5k-1)$

If $k=-\frac45$ , then

$1=b(-4-1)\implies b=-\frac15$

If $k=\frac15$ , then

$1=a(1+4)\implies a=\frac15$

This means

$\dfrac{10}{(5k-1)(5k+4)}=\dfrac2{5k-1}-\dfrac2{5k+4}$

Consider the $n$ th partial sum of the series:

$S_n=2\left(\dfrac14-\dfrac19\right)+2\left(\dfrac19-\dfrac1{14}\right)+2\left(\dfrac1{14}-\dfrac1{19}\right)+\cdots+2\left(\dfrac1{5n-1}-\dfrac1{5n+4}\right)$

The sum telescopes so that

$S_n=\dfrac2{14}-\dfrac2{5n+4}$

and as $n\to\infty$ , the second term vanishes and leaves us with

$\displaystyle\sum_{k=1}^\infty\frac{10}{(5k-1)(5k+4)}=\lim_{n\to\infty}S_n=\frac17$

7 0

2 years ago

What is the equation of a line that passes through the points (1,6) and (2,1)?

algol13

Answer:

y = -5x+11

Step-by-step explanation:

3 0

2 years ago

This is to help my wonderful mother. What is 1/3rd of 4 1/2s and 8 1/4s?

crimeas [40]

4 1/2 = 9/2
8 1/4 = 33/4

1/3 x 9/2 = 3/2
1/3 x 33/4 = 33/12

5 0

3 years ago